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Ksenya-84 [330]
4 years ago
5

Kate swam 18 laps at practice This is three fourths The number Of laps that paco swam at practice write an equation that can be

used to find the number of laps that paco swam
Mathematics
1 answer:
Lunna [17]4 years ago
5 0
18÷4=5×3=15 laps that paco swam
You might be interested in
I really don't understand this I need help
Salsk061 [2.6K]
In looking at it I would guess it is asking which of the points is on the line? To answer that you would have to take each point an plug it into the equation and see if it is true.

3x - 7 = y

A(9,20)  
3(9) - 7 = 20
27 - 7 = 20
20 = 20 True - this point is on the line

B(5,0)
3(5) - 7 = 0
15 - 7 = 0
8 = 0 False - this point is not on the line

C(3,2)
3(3) - 7 = 2
9 - 7 = 2
2 = 2  True - this point is on the line

I hope this helps
7 0
3 years ago
Min-Jee is planting two rectangular flower beds. One bed is 2.78 feet by 4.81 feet, and the other bed is 2.78 feet by 5.61 feet.
shusha [124]

Answer:  (2.78+4.81)(2.78+5.61)

Step-by-step explanation:

<h3> The complete exercise is attached.</h3><h3></h3>

The area of a rectangle can be calculated with this formula:

A=lw

Where "l" is the lenght and "w" is the width.

Then, you can notice that it can be obtained by multiplying the dimensions of the rectangle.

Knowing this, you can determine that the total area of the two flowers bed can be obtained by adding the products of their dimensions.

Since one of the rectangular flower bed is 2.78 feet by 4.81 feet and the other bed  2.78 feet by 5.61 feet, you can write the following expression to find the total area (in square feet)of the two beds:

2.78*4.81 +2.78*5.61

If you factor out 2.78:

2.78(4.81 +5.61) or (4.81 +5.61)2.78

Therefore, the expression that does not represent the total area in square feet of the two beds, is:

(2.78+4.81)(2.78+5.61)

6 0
3 years ago
Read 2 more answers
Five buses leave on a field trip .There are about 45 students per bus.About how many students are on the 5 buses.
dangina [55]
45 x 5 = 225 so 225 students altogether on 5 buses
7 0
3 years ago
Read 2 more answers
An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
3 years ago
Matteo has &amp;400 in his saving account. On average he spends $10 per week on buying apps. Luca has $200 in his savings accoun
n200080 [17]

Answer: By the 8th week.

Step-by-step explanation:

Let the time that matteo and luca have the same amount of money be represented by x.

The information given in the question can be formed into an equation as:

400 - 10x = 200 + 15x

Collect like terms

400 - 200 = 15x + 10x

200 = 25x

x = 200/25

x = 8

Matteo and Luca will have the same amount of money by the 8th week.

4 0
3 years ago
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