The frequency of the wave is A
Answer:
No, although the bean crop can grow perfectly in full sun or a little shade in very warm places. It does not mean that they will adopt the growth patterns of the cactus, especially because this plant needs constant watering (in small quantities), very constant. Beans require good drainage for their growth.
<h3><u>Answer;</u></h3>
0.002512 moles of H2O
<h3><u>Explanation</u>;</h3>
The reaction between acetic acid ( CH3COOH) and NaOH is given by the equation;
CH3COOH + NaOH ------> CH3COONa + H2O
Number of moles of CH3COOH = molarity × volume in litres
= 0.08 × 31.4/1000
= 2.512 × 10^-3
Similarly number of moles of NaOH = 1 × 24.3/1000
= 0.0243
From the reaction the mole ratio of CH3COOH : NaOH
Therefore; 0.0243 moles of NaOH will react with 0.0243 moles of CH3COOH but no.of moles of CH3COOH given in the question are 0.002512 moles, which is less than what is required.
Thus; CH3COOH is the limiting reagent and amount of products produced will depend on amount of CH3COOH only.
Since; 1 mole of CH3COOH gives 1 mole of water.
Then; 0.002512 moles of CH3COOH will give 0.002512 moles of H2O
1 g/mL ------------ 8.3454 lbs/gal
1.09 g/mL --------- ?
lbs/gal = 1.09 x 8.3454 / 1
ibs/gal = 9.096 / 1
= <span>9.096 lbs/gal</span>
Answer:
4O₂ (g) + 1/2C₅H₁₂ (g) → 5/2CO₂ (g) + 3H₂O (g)
4 would be the smallest possible integer for O₂
Explanation:
The balanced equation is this one:
8O₂ (g) + C₅H₁₂ (g) → 5CO₂ (g) + 6H₂O (g)
If we divide stoichiometry /2 (the half) we can consider that we use, the smallest possible integers.
8/2O₂ (g) + 1/2C₅H₁₂ (g) → 5/2CO₂ (g) + 6/2H₂O (g)
4O₂ (g) + 1/2C₅H₁₂ (g) → 5/2CO₂ (g) + 3H₂O (g)
