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ella [17]
3 years ago
12

Compare the nuclear charge of nitrogen to oxygen on the valance electrons.

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer: well the the nuclear charge of nitrogen is 7

but the Oxygen is in the 6A group which means that oxygen has 6 valence electrons.

Explanation:

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How many equivalents are present in 13.5g of Al3+
gogolik [260]
Answer:

= 1.5 eq

Explanation:

One definition of an equivalent weight is that it is mass of a substance that gains or loses 1 mole of electrons.
Al3+ has lost 3 e-, so there are 3 equivalent weights in 1 mol Al3+.

1 mol Al3+ =3 eq. wts.
1 mol Al x(27 g / 1 mol)x(1 mol / 3 eq. wts.) = 9.0 g = 1 eq. wts.

13.5 g Al3 + x (1 eq.wt. / 9.0 g) = 1.5 eq
4 0
3 years ago
How to solve partial pressure given water vapor pressure?
CaHeK987 [17]
The partial pressure<span> of </span>water<span> in the mixture, P</span>water<span>, is the equilibrium </span>vapour pressure<span> of </span>water<span> at the temperature specified. At 298 K, from the data at the beginning of the questions section, P</span>water<span> = 3.17 kPa. Using the Ideal Gas Equation, the number of moles of N</span>2<span> can be calculated.</span>
6 0
3 years ago
Which of the following is an oxidation-reduction reaction? so2(g) h2o(l) right arrow. h2so3(aq) caco3(s) right arrow. cao(s) co2
Gennadij [26K]

The reaction which shows oxidation and reduction simultaneously is C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l).

<h3>What are redox reactions?</h3>

Those reaction in which oxidation as well as reduction of substances takes place simultaneously will known as redox reactions.

  • SO₂(g) + H₂O(l) → H₂SO₃(aq)
  • CaCO₃(aq) → CaO(s) + CO₂(g)
  • Ca(OH)₂(s) + H₂CO₃(l)  CaCO₃(aq) + 2H₂O(l)

Above reaction are not the redox reactions as in these reaction oxidation and reduction simultaneously not takes place.

  • C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l)

In the above reaction reduction of oxygen takes place as its oxidation state changes from 0 to -2, and at the same time oxidation of carbon takes place as its oxidation state changes from 0 to +4.

Hence correct option is (4).

To know more about redox reactions, visit the below link:
brainly.com/question/7935462

7 0
2 years ago
Read 2 more answers
Which of the following is not equal 225 g?
vekshin1
G to dkg is 1 place to the right, move the decimal point 1 place to the left 
<span>225 g = 22.5 dkg 
C is the answer</span>
3 0
3 years ago
Read 2 more answers
1. Unas de las formas de producir nitrógeno gaseoso (N2) es mediante la oxidación de metilamina (CH3NH2), tal como se muestra en
Maslowich

Answer:

a) 4CH₃NH₂ + 9O₂ ⇄  4CO₂ + 10H₂O + 2N₂    

b) m = 5,043 g

c) % = 69,4 %

Explanation:

a) La ecuación balanceada es la siguiente:

4CH₃NH₂ + 9O₂ ⇄  4CO₂ + 10H₂O + 2N₂              

En el balanceo, se tiene en la relación estequiométrica que 4 moles de metilamina reacciona con 9 moles de oxígeno para producir 4 moles de dióxido de carbono, 10 moles de agua y 2 moles de nitrógeno.  

b) Para determinar la masa de nitrógeno se debe calcular primero el reactivo limitante:

n_{O_{2}} = \frac{m}{M} = \frac{25,6 g}{31,99 g/mol} = 0,800 moles      

n_{CH_{3}NH_{2}} = \frac{4}{9}*0,800 moles = 0,356 moles

De la ecuación anterior se tiene que la cantidad de moles de metilamina necesaria para reaccionar con 0,800 moles de oxígeno es 0,356 moles, y la cantidad de moles iniciales de metilamina es 0,5 moles, por lo tanto el reactivo limitante es el oxígeno.

Ahora, podemos calcular la masa de nitrógeno producida:

n_{N_{2}} = \frac{2}{9}*n_{O_{2}} = \frac{2}{9}*0,8 moles = 0,18 moles

m_{N_{2}} = n_{N_{2}}*M = 0,18 moles*28,014 g/mol = 5,043 g

Por lo tanto, se pueden producir 5,043 g de nitrógeno.

c) El redimiento de la reacción se puede calcular usando la siguiente fórmula:

\% = \frac{R_{r}}{R_{T}}*100

<u>Donde</u>:

R_{r}: es el rendimiento real

R_{T}: es el rendimiento teórico

\% = \frac{3,5}{5,043}*100 = 69,4

Entonces, el procentaje de rendimiento de la reacción es 69,4%.

Espero que te sea de utilidad!        

5 0
3 years ago
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