Answer:
THERE IS NOTHING SHOWN BELOW
Answer:
Step-by-step explanation:
It says Renita takes minutes to ride half a mile.
She leaves 30 minutes before school.
Total distance is
![2\frac{1}{2} = \frac{1}{2}+ \frac{1}{2} +\frac{1}{2} +\frac{1}{2} +\frac{1}{2}\\](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%5C%5C)
In
![2\frac{1}{2} \ there \ are \ 5 \ times \ \frac{1}{2} \ mile .\\](https://tex.z-dn.net/?f=2%5Cfrac%7B1%7D%7B2%7D%20%5C%20there%20%5C%20are%20%5C%205%20%5C%20times%20%20%5C%20%20%5Cfrac%7B1%7D%7B2%7D%20%5C%20mile%20.%5C%5C)
Therefore total time to reach school will be 5 x 5 = 25minutes.
Since she leaves 30minutes before school. She will reach 5minutes early before school.
Answer:
92/85
Step-by-step explanation:
Height of Dougal = 1.84 meters
Height of Seb = 1.7 meters
Height of Dougal as a fraction of height of Sab = ![\frac{1.84}{1.7}](https://tex.z-dn.net/?f=%5Cfrac%7B1.84%7D%7B1.7%7D)
=
[Simplify the fraction]
= ![\frac{184}{170}](https://tex.z-dn.net/?f=%5Cfrac%7B184%7D%7B170%7D)
= ![\frac{92}{85}](https://tex.z-dn.net/?f=%5Cfrac%7B92%7D%7B85%7D)
Therefore, fraction of heights will be = 92/85
Answer:
The dimension of A is L/T^3 and the dimension of B is L/T
Step-by-step explanation:
We can write the equation but just in terms of its dimensions and work with dimension analysis to find the dimensions of the constants.
Writing the dimensions equation.
For the given equation
![x = At^3+Bt](https://tex.z-dn.net/?f=x%20%3D%20At%5E3%2BBt)
We can write
![[x]=[A][t]^3+[B][t]](https://tex.z-dn.net/?f=%5Bx%5D%3D%5BA%5D%5Bt%5D%5E3%2B%5BB%5D%5Bt%5D)
We can then replace the dimensions where x is a length dimension which means
and t has a time dimension,
, so we get
![L = [A]T^3+[B]T](https://tex.z-dn.net/?f=L%20%3D%20%5BA%5DT%5E3%2B%5BB%5DT)
Since we are adding terms on the right side both terms must have the same dimension. That means we have
![[A]T^3=L](https://tex.z-dn.net/?f=%5BA%5DT%5E3%3DL)
And
![[B]T=L](https://tex.z-dn.net/?f=%5BB%5DT%3DL)
Finding the dimensions of A and B
We can finally solve for the dimensions of each.
For A we have
![[A]T^3=L\\](https://tex.z-dn.net/?f=%5BA%5DT%5E3%3DL%5C%5C)
Solving for [A] will give us
![\boxed{[A] = \cfrac{L}{T^3}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5BA%5D%20%3D%20%5Ccfrac%7BL%7D%7BT%5E3%7D%7D)
Solving for [B]
![[B]T=L](https://tex.z-dn.net/?f=%5BB%5DT%3DL)
![\boxed{[B]=\cfrac LT}](https://tex.z-dn.net/?f=%5Cboxed%7B%5BB%5D%3D%5Ccfrac%20LT%7D)
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