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vredina [299]
4 years ago
5

Suppose you decide to define your own temperature scale using the freezing point (13 ∘c) and boiling point (360 ∘c) of oleic aci

d, the main component of olive oil. if you set the freezing point of oleic acid as 0 ∘o and the boiling point as 140 ∘o, what is the freezing point of water on this new scale?
Chemistry
1 answer:
tino4ka555 [31]4 years ago
8 0
<span>Assume new scale as deg O. To find incremental scale of deg C against deg O, (360 - 13) / (140 - 0) = 2.48. This implies there will be an increment of 2.48 deg C for every increment of 1 deg O. Freezing point of water ( 0 deg C ) will become (0 - 13) / 2.48 = - 5.24 deg O. Temperature will be negative as 0 deg O corresponds to 13 deg C and hence any temperature below that will be negative.</span>
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The answers are as follows,

1. 4.71 L,

2. 3.29 L,

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Rearranging the above expression, we get,

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1) The first case can be solved as,

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2) The second case can be solved as,

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3) The third case can be solved as,

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1. 4.71 L,

2. 3.29 L,

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