1) first, we have to convert the grams to moles of AuCl3 using the molar mass of the molecule.
molar mass of AuCl3= 197 + (35.5 x 3)= 303.5 g/mol
73.4 g (1 mol AuCl3/ 303.5 g)= 0.242 moles
2) now. let's convert moles of AuCl3 to moles of chlorine gas (Cl2) using the mole-mole ratio
0.242 mol AuCl3 (3 mol Cl2/ 2 mol AuCl3)= 0.363 mol Cl2
3) finally, we convert moles to grams using the molar mass of Cl2.
molar mass of Cl2 = 35.5 x 2= 71.0 g/mol
0.363 mol Cl2 ( 71.0 g/ 1 mol)= 25.8 grams
Answer:
1223.38 mmHg
Explanation:
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 
Also,
Moles = mass (m) / Molar mass (M)
Density (d) = Mass (m) / Volume (V)
So, the ideal gas equation can be written as:
Given that:-
d = 1.80 g/L
Temperature = 32 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (32 + 273.15) K = 305.15 K
Molar mass of nitrogen gas = 28 g/mol
Applying the equation as:
P × 28 g/mol = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K
⇒P = 1223.38 mmHg
<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>
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Answer:
73.68 J
Explanation:
To find the energy absorbed by nickel, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = energy (J)
-----> m = mass (g)
-----> c = specific heat (J/g°C)
-----> ΔT = change in temperature
The change in temperature is found by subtracting the initial temperature from the final temperature. You can plug the given values into the equation and simplify to find the energy absorbed.
m = 10.0 g
c = 0.120 J/g°C
ΔT = 63.4 °C - 2.0 °C = 61.4 °C
Q = mcΔT
Q = (10.0 g)(0.120 J/g°C)(61.4 °C)
Q = 73.68 J
<u>Given:</u>
Moles of CS2 (it cannot be CO2 as mentioned in the question, since O2 reacts with CS2 and not CO2) = 34.5 mol
<u>To determine:</u>
Moles of O2 undergoing the reaction
<u>Explanation:</u>
The reaction is-
CS2 + 3O2 → CO2 + 2SO2
Based on the stoichiometry: 3 moles of O2 reacts with 1 mole of CS2
therefore the moles of O2 that would combine with 34.5 moles of CS2 are
= 3 moles O2 * 34.5 moles CS2/1 mole CS2 = 103.5 moles
Ans: Around 104 moles of O2 would react with 34.5 moles of CS2
