Answer:
d.miscible
Explanation:
If two liquids are completely miscible, no interfacial tension exists between them.
Interfacial tension is the force of attraction between between the molecules of a fluid that are in contact. This tension forms thick skin at the interface.
In miscible liquids, in which one liquid completely dissolves in another, there is no interfacial tension.
Interfacial tension does not allow miscibility of fluids as the tension between the interface is too great.
- When there is a condition of no interfacial tension, two liquids are miscible.
- When there is immiscibility, interfacial tension exists between two fluids and this invalidates option A.
So, if two liquids are miscible, there is no interfacial tension between them.
<span>N2</span>+3<span>H2</span>→2N<span>H<span>3 hope this helps
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218.4 grams of CaO is produced using 3.9 moles CaCO₃.
<h3>How we calculate weight of any substance from moles?</h3>
Moles of any substance will be defined as:
n = W / M
Given chemical reaction is:
CaCO₃ → CaO + CO₂
From the above equation it is clear that according to the concept of stoichiometry 1 mole of CaCO₃ is producing 1 mole of CaO. By using above formula, we calculate grams as follow:
W = n × M, where
n = no. of moles of CaO = 3.9 moles
M = molar mass of CaO = 56 g/mole
W = 3.9 × 56 = 218.4 g
Hence, 218.4 grams of Cao is produced.
<h3>How much grams do Cao's molecular weight equal?</h3>
Molecular weight of CaO. CaO has a molar mass of 56.0774 g/mol. Calcium Oxide is another name for this substance. Convert moles of CaO to grams or grams of CaO to moles. Calculation of the molecular weight: 40.078 + 15.9994 ›› Composition by percentage and element
<h3>How much calcium is required to create one mole of oxygen?</h3>
In order to create one mole of calcium oxide, the reaction between one mole of calcium (40.1 g) and half a mole of oxygen (16 g) is stoichiometric (56.1 g). This means that only 4.01 grams of calcium metal and 1.6 grams of oxygen can combine to generate 5.61 grams of calcium oxide.
Learn more about moles:
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