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lesya [120]
3 years ago
9

Mr. Townes created a 2-foot wide garden path around a circular garden. The radius of the garden is 7 feet. He wants to cover the

path in stones. If Mr. Townes needs 1 bag of stones for every 5 square feet of path, how many bags of stones will he need 5o cover his garden path?

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0
See photo for solution

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Helppppp!!!!!! Plsss
PtichkaEL [24]

Answer:

A!

Step-by-step explanation:

open circle = the number it's on isn't an answer

the arrow is pointing left, the negative side so it's less than :)

6 0
3 years ago
What is the correct answer
tiny-mole [99]
Take a look at all 3 expressions: numbers, terms, and exponents.

4, 8, and 6 all have a GCF of 2.

y^5, y^3, and y^2 have a GCF of y^2.

Therefore, the GCF is 2y^2. Removing it gets you:

2y^2(2y^3 + 4y - 3)
5 0
3 years ago
A long distance runner ran 4x4x4x4x4x4 miles last year. How many miles is this?
Archy [21]

Answer:

4096

Step-by-step explanation:

4x4x4x4x4x4=4^6

Group them to multiply to make it easier:

4x4=16

4x4=16

4x4=16

16x16x16=4096

honestly just plug it into a calculator

3 0
3 years ago
Read 2 more answers
What is 7x-4y+2x+8y in distributive form? I will give brainliest and 100 points. Thank you.
alexgriva [62]

Answer:

4(2 1/4x + y)

Step-by-step explanation:

Just factor

In this cae no GCF

So just divide By 4 becuase its easy

If you solve it

You’d get 9x+4y

WHich is the combined term of the expression given

5 0
3 years ago
Read 2 more answers
EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
\implies x=\dfrac23,x=2

are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
4 0
4 years ago
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