Ask question

Ask question

All categories

3 years ago

8

The markup over the dealer's cost on a new refrigerator ranges from 15% to 20%. If the dealer's cost is $1750, over what rage wi

ll the selling price vary?

1 answer:

jok3333 [9.3K]3 years ago

6 0

The markup will range from $2012.50 to $2100.

You might be interested in

What's the pattern in 30 21 12 3 -6

Bas_tet [7]

$a_b=39 - 9b$

3 0

3 years ago

Read 2 more answers

Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc

In-s [12.5K]

Answer:

$\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

$L^2 = y^2 + x^2$

$\implies L = \sqrt{y^2 + x^2}$ ,

Differentiating with respect to time (t),

$\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})$

$=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)$

$=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})$

$=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Here,

$\frac{dy}{dt}=-6\text{ ft per sec}$

Also, $\frac{dL}{dt} = 0$ ( Ladder length = constant ),

$\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0$

$-6x + y\frac{dy}{dt}=0$

$y\frac{dy}{dt}=6x$

$\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Which is the required notation.

8 0

3 years ago

What would -9 1/2 be as a decimal?

Kamila [148]

-9.5 because 1/2 simplifies to .5 and 9 is the whole number

3 0

3 years ago

Read 2 more answers

never [62]

Answer:

hi

Step-by-step explanation:

Perdon si no te ayudo pero solo quiero los puntos para mis preguntas

6 0

2 years ago

Olenka [21]

Answer:

B.8K-168/K-12

4 0

3 years ago