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3 years ago

8

The markup over the dealer's cost on a new refrigerator ranges from 15% to 20%. If the dealer's cost is $1750, over what rage wi

ll the selling price vary?

1 answer:

jok3333 [9.3K]3 years ago

6 0

The markup will range from $2012.50 to $2100.

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

Hope this wasn't too confusing! I'll answer any questions.

8 0

2 years ago

Read 2 more answers

An acute triangle has side lengths 21 cm, x cm, and 2x cm. if 21 is one of the shorter sides of the triangle, what is the greate

madam [21]

Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm

Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side

For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm

If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm

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2 years ago

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Worth more<br> Points!!!!

Lilit [14]

-72-4x^2+8x^3-36x/x-3

-4(18+x^2-2x^3+9x)/x-3

-4(-2x^3+x^2+9x+18)/x-3

-4(-2x^2x(x-3)-5x x(x-3)-6(x-3) )/x-3

-4 x(-(x-3) ) x (2x^2+5x+6)/x-3

-4 x (-1) x (2x^2 +5x+6)

8x^2+20x+24

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3 years ago

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What is the constant ratio formula

Zigmanuir [339]

DEFINITION of 'Constant Ratio Plan' Aconstant ratio plan is a strategic asset allocation strategy, or formula, which keeps the aggressive and conservative portions of a portfolio set at a fixedratio.

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2 years ago

What is the maximum value of the objective function, P, with the given constraints?

maksim [4K]

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

$P=20x+35y$

Constraints,

$x+y \leq 12$

$5x+y \leq 20\\x \geq 0\\y \geq 0$

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

$P=20x+35y$

Point (0,0)

$P=20(0)+35(0)=0$

$P=20x+35y$

Point (0,12)

$P=20(0)+35(12)=420$

Point (2,10)

$P=20(2)+35(10)=40+350=390$

Point (4,0)

$P=20(4)+35(0)=80$

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

8 0

3 years ago