Answer:
1456 N
Explanation:
Given that
Frequency of the piano, f = 27.5 Hz
Entire length of the string, l = 2 m
Mass of the piano, m = 400 g
Length of the vibrating section of the string, L = 1.9 m
Tension needed, T = ?
The formula for the tension is represented as
T = 4mL²f²/ l, where
T = tension
m = mass
L = length of vibrating part
F = frequency
l = length of the whole part
If we substitute and apply the values we have Fri. The question, we would have
T = (4 * 0.4 * 1.9² * 27.5²) / 2
T = 4368.1 / 2
T = 1456 N
Thus, we could conclude that the tension needed to tune the string properly is 1456 N
Team work and a can do attitude is very important when being a team worker, as well as being open minded!
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Answer:
The average velocity is 40km/h.
Explanation:
The average velocity is 
, where 
is the distance traveled and 
the time elapsed.
The distance traveled is clearly 80km since it's all done in the same direction, we only need to know the time elapsed. For this we calculate the time elapsed on the first part, and add it to the time elapsed on the second part using always the formula 
, where v is the velocity on each part, which is constant.
The time elapsed for the first part is 
, and the time elapsed for the second part is 
, giving us a total time of 
=2h.
Finally, we can calculate the average velocity: 
.
Answer:
The way in which objects exert forces on each other is described by Newton’s 3rd law of motion
Explanation:
Objects with mass exert forces on each other via the force of gravity. This force is proportional to the mass of the two interacting objects and is inversely proportional to the square of the distance between them. The factors G, M, and rare the same for all masses at the surface of the Earth.
Answer:
4.25 s
Explanation:
Given:
angular acceleration'α'= 1.8 rad/s²
angle 'θ'= 45 rad
time 't'= 4s
initial angular velocity '
'=0
as we know that,
θ= 
t + 
45 = 4 + (0.5 x 1.8 x 16)
45- 14.4 = 4
30.6 = 4
= 7.65
Next is to find t by using the equation
= + 
7.65= 0 + (1.8)
= 7.65/1.8
= 4.25 s
Therefore, At the start of 4s interval the motion is at 4.25 second
