An object experiences an acceleration of 6.8m/s2.As a result,it accelerates from rest to 24m/s.How much distance did it travel d

Question

3 years ago

8

uring that acceleration

1 answer:

Hitman42 [59] · Answer 1 · 2022-06-16T12:20:21+03:00

The distance covered by the object is 42.4 m

Explanation:

The motion of the object is a uniformly accelerated motion (at constant acceleration), therefore we can use the following suvat equation:

$v^2 -u^2 = 2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the object in this problem, we have:

u = 0 (it starts from rest)

v = 24 m/s (final velocity)

$a=6.8 m/s^2$

Solving for s, we find the distance travelled by the object:

$s=\frac{v^2-u^2}{2a}=\frac{24^2-0}{2(6.8)}=42.4 m$

Learn more about accelerated motion:

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