Answer:
a) yield strength

b) modulus of elasticity
strain calculation

strain for offset yield point

=0.0046-0.002 = 0.0026
now, modulus of elasticity
= 184615.28 MPa = 184.615 GPa
c) tensile strength

d) percentage elongation

e) percentage of area reduction
(186,000 mi/sec) x (3,600 sec/hr) x (24 hr/da) x (365 da/yr)
= (186,000 x 3,600 x 24 x 365) mi/yr
= 5,865,696,000,000 miles per year (rounded to the nearest million miles)
By looking at how wiggily the bar is lol
Answer:
The mass of Uranium present in a 1.2mg sample is 
Explanation:
The ration between Uranium mass and total sample mass is:
For a sample of mass 1.2 mg, the amount of uranium is:

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