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UNO [17]
3 years ago
5

What is a limiting factor for the red-eyed tree frog?

Chemistry
1 answer:
Law Incorporation [45]3 years ago
6 0
A limiting factor could be disease
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By process of incineration, a mystery substance is empirically determined to contain 40.00% carbon by weight, 6.67% hydrogen, an
Keith_Richards [23]

Answer:

C₂H₄O₂

Explanation:

Step 1: Divide each percentage by the atomic mass of the element

C: 40.00/12.01 = 3.331

H: 6.67/1.01 = 6.60

O: 53.33/16.00 = 3.333

Step 2: Divide all the numbers by the smallest one

C: 3.331/3.331 = 1

H: 6.60/3.331 ≈ 2

O: 3.333/3.331 ≈ 1

The empirical formula is CH₂O, with a molecular weight of 12 g/mol + 2 × 1 g/mol + 16 g/mol = 30 g/mol. The molecular weight of the compound must be a product of 30, such as 60 (between 55 and 62 g/mol). Since we have to multiply by 2 (30 to 60) to get to the molecular weight of the compound, we also have to multiply the empirical formula by 2 to get the chemical formula of the compound.

CH₂O × 2 = C₂H₄O₂

4 0
3 years ago
Why doesn't the stomach acid just digest right through the wall of the stomach? Select one: a.Neutralizers are imbedded in the s
Lostsunrise [7]

Answer:

d

Explanation:

5 0
3 years ago
Read 2 more answers
A warm ocean transfers heat to the air above it. Which type of heat transfer is this
Zigmanuir [339]

Answer:

Conduction

Explanation:

Because When air is  in contact with the ocean it is at a different temperature than the seas surface

7 0
3 years ago
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The smaller radius is primarily a result of the magnesium atom having ??
Aleksandr [31]

Answer:

A larger nuclear charge :)

Explanation:

8 0
3 years ago
What is amu of 99 % H-1, .2% H-1 and .8% H-3
ankoles [38]

The average atomic mass of your mixture is 1.03 u .

The average atomic mass of H is the weighted average of the atomic masses of its isotopes.  

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).  

Thus,  

0.99    × 1.01 u = 0.998 u

0.002 × 2.01 u = 0.004 u

0.008 × 3.02 u = <u>0.024 u</u>

            TOTAL =  1.03   u

4 0
3 years ago
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