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Marianna [84]
3 years ago
7

The d-metals iron, copper, and manganese form cations with different oxidation states. For this reason, they are found in many o

xidoreductases and in several proteins of oxidative phosphorylation and photosynthesis. Explain why many d-metals form cations with different oxidation states.
Chemistry
2 answers:
kicyunya [14]3 years ago
8 0

Answer:

==> Presence of unpaired electrons.

==> Electrons in ns and electrons in (n-1)d orbitals are used to form bonds because of their similarities in energies.

Explanation:

The d- metals are also known as the transition metals with metal elements such as the ones given in the question, that is; Copper, iron and Manganese. Others include chromium, Nickel, Cobalt and so on.

The reason behind many d-metals forming cations with different oxidation states is mainly because of the unpaired electrons. Because Unpaired electrons are unstable they tends to attract or bond with other species chemically.

Also, many d-metals form cations with different oxidation states because Electrons in ns and electrons in (n-1)d orbitals are used to form bonds because of their similarities in energies.

choli [55]3 years ago
4 0

Answer:

They have electrons in their 3d- and 4s-orbital for bond formation.

Explanation:

d- metals or transition metal are metal which form ion with partially filled d-orbital. Examples are iron and manganese.

The metals have 2 electrons in their 4s orbital. If only this is used for bonding, they will form compounds where they have oxidation State of +2 as seen in MnO.

If two 4s and one of 3d electrons are used, oxidation state of +3 is formed as seen in FeCl3.

If two 2s electron I used with two 3d electrons, compound with oxidation state of +4 is formed as seen in MnO2

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How many grams of NH3 can be produced from 4.98 mol of N2 and excess H2
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The periodic table has undergone some changes since it was first introduced. List three ways the modern periodic table differs f
Hoochie [10]
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6 0
2 years ago
The density of mercury is 13.6 g/cm'. How many quarts does 83.0 g of Hg occupy? (1 L=1.06 qt)​
forsale [732]

Answer:

0.0064 qt

Explanation:

Given data:

Density of mercury = 13.6 g/cm³

Mass of mercury = 83.0 g

How many quarts mercury have = ?

Solution:

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d = m/v

13.6 g/cm³ = 83.0 g / volume

Volume = 83.0 g /  13.6 g/cm³

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6.1 cm³ × 1 L / 1000  cm³

0.0061 L

In quarts:

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0.0061 L × 1.06 qt / 1 L

0.0064 qt

4 0
3 years ago
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