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3 years ago

Which statement best applies collision theory to preventing a dangerous reaction from occurring?

Chemistry

2 answers:

dusya [7]3 years ago

7 0

Answer:

Particles need to collide in order to react

Explanation:

If they don't collide, they cant react.

puteri [66]3 years ago

4 0

There is no answer choices i need answer choices you said which i cant say which one it is if i dont have answer choices

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How many magnesium atoms are in the product

strojnjashka [21]

Answer: Im not sure if you are doing this in your class.

Explanation:

So... for the element of MAGNESIUM, you already know that the atomic number tells you the number of electrons. That means there are 12 electrons in a magnesium atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and two more in shell three

5 0

3 years ago

CADMIUM SOLUBILITY AND pH Cadmium is a toxic metal. It can be removed from water by chemical precipitation of solid cadmium hydr

Serga [27]

Explanation:

It is known that,

Molar mass of Cd = 112.41 g/mol

Standard concentration of Cd = 0.005 mg/L = $0.005 \times 10^{-3}$ g/L

Hence, we will calculate the molarity as follows.

Molarity = $\frac{0.005 \times 10^{-3}}{112.41} mol/L$

= $4.45 \times 10^{-8}$ M

Equation for the reaction is as follows.

$Cd(OH)_{2} \rightleftharpoons Cd^{2+} + 2OH^{-}$

$K_{sp} = [Cd^{2+}][OH^{-}]^{2}]$

$2 \times 10^{-34} = 4.45 \times 10^{-8} \times [OH^{-}]^{2}$

$[OH^{-}] = 6.7 \times 10^{-4}$ M

Also,

$[H^{+}] = \frac{10^{-14}}{[OH^{-}]}$

= $\frac{10^{-14}}{6.7 \times 10^{-4}}$

= $1.49 \times 10^{-11} M$

Relation between pH and concentration of hydrogen ions is as follows.

pH = $-log [H^{+}]$

= $-log (1.49 \times 10^{-11} M)$

= 10.82

Thus, we can conclude that a minimum pH of 10.82 is necessary to reduce the dissolved cadmium ion concentration to the standard.

4 0

3 years ago

I need answers to question 1,2,3

sashaice [31]

Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole of Ca(NO₃)₂ =?

Mole = mass /molar mass

Mole of Ca(NO₃)₂ = 100 / 164

Mole of Ca(NO₃)₂ = 0.61 mole

6 0

3 years ago

Which of these elements has physical and chemical properties most similar to Sulfur (S)?

andreev551 [17]

A) Selenium - is apart of Sulfur family

8 0

3 years ago

Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid

Phoenix [80]

Answer:

pH = 8.0

Explanation:

First, we have to calculate the moles of NaOH.

$35.8 \times 10^{-3}L.\frac{0.020mol}{L} =7.2\times 10^{-4}mol$

Let's consider the balanced equation.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio C₂H₄O₃: NaOH: C₂H₃O₃Na is 1: 1: 1. So, when 7.2 × 10⁻⁴ moles of NaOH react completely with 7.2 × 10⁻⁴ moles of C₂H₄O₃ they form 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

The concentration of C₂H₃O₃Na is:

$\frac{7.2\times 10^{-4}mol}{60.8 \times 10^{-3}L} =0.012M$

C₂H₃O₃Na dissociates according to the following equation:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

C₂H₃O₃⁻ comes from a weak acid so it undergoes basic hydrolisis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

If we know that pKa for C₂H₄O₃ is 3.9, we can calculate pKb for C₂H₃O₃⁻ using the following expression:

pKa + pKb = 14

pKb = 14 -3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can calculate [OH⁻] using the following expression:

[OH⁻] = √(Kb.Cb) <em>where Cb is the initial concentration of the base</em>

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

Now, we can calculate pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

7 0

3 years ago