<span> d. Reduced visibility
Acid rain doesn't reduce visibility, smog does
</span>
Answer:
B. 1.65 L
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g)
Step 2: Calculate the moles of SO₂
The pressure of the gas is 1.20 atm and the temperature 25 °C (298 K). We can calculate the moles using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.20 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298 K = 0.0736 mol
Step 3: Calculate the moles of SO₃ produced
0.0736 mol SO₂ × 2 mol SO₃/2 mol SO₂ = 0.0736 mol SO₃
Step 4: Calculate the volume occupied by 0.0736 moles of SO₃ at STP
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.0736 mol × 22.4 L/1 mol = 1.65 L
Answer:
Decomposition of aluminium oxide forms aluminium atoms and oxygen atoms.
Explanation:
<u>Decomposition reaction:</u>
When a single compound break down into two or more simpler products.
For example "AB" reactant undergoes decomposition to form "A" and "B" products.
The chemical reaction is as follows.
The given compound is aluminium oxide.
The decomposition reaction of aluminium oxide is a follows.
The balanced equation is as follows.
Therefore, Decomposition of aluminium oxide forms aluminium atoms and oxygen atoms.
<h3>Further explanation
</h3>
In general, some people equate mass and weight.
Mass is one of the principal quantities, which is related to the matter , whereas weight is a force that leads to the center of the earth (Earth's gravitational force)
Steps that can be taken to find the mass :
- 1. Weigh graduated cylinder (empty)
- 2. Pour the alcohol in the beaker into the graduated cylinder to the level of 40 ml
- 3. Weigh again graduated cylinder + poured alcohol
- 4. mass of alcohol 40 ml = mass in 3rd step - mass in the first step
Arsenic, I believe. Metalloids fall in between metals and nonmetals (usually on the bold line separating the two on the periodic table). And since the metalloid in question has four electron shells and five valence electrons in the outermost shell, you can see that this element is arsenic
