Answer:
The answer to your question is 64.02 g of H₂O
Explanation:
Data
Mass of magnesium sulfate hepta hydrated = 125 g
Mass of water = ?
Process
1.- Calculate the molar mass of the salt and the molar mass of water
molar mass of MgSO₄ 7H₂O = 24 + 32 + 64 + 14 + 112 = 246 g
mass of H₂O = 2 + 16 = 18 g
2.- Use proportions to calculate the mass of water in the epsom salt
246 g MgSO₄ 7H₂O------------------------- 126 g of H₂O
125 g ------------------------- x
x = (125 x 126)/246
x = 15750/246
x = 64.02 g of H₂O
I’m pretty sure it’s sulphur dioxide
To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit
From the equation q=mCΔT, set the q of copper = to q of water,
So --- mCΔT(copper)=mCΔT(water).
mass (Cu - copper) = 38g
mass (H2O - water) = 15g
C (H2O) = 4.184 J/g*C
ΔΤ (H2O) = 33-22 = 11*C
ΔΤ (Cu) = 33-80 = -47*C (the final temp is the same for both materials - thermal equilibrium)
C (Cu) = ?
So --- 38(-47)C[Cu]=15(4.184)(11)
--- C[Cu]=690.36/(-1786) = 0.3865 J/g*C, or 0.39 in 2 sig figs. (The negative goes away, because specific heats are usually positive)
Answer:
False. The balanced equation should be
2KClO3-->2KCl + 3O2
it is a decomposition reaction.