Answer:
a)
b)
Explanation:
a) The reaction:
The free-energy expression:
![E=E_{red}-E_{ox]](https://tex.z-dn.net/?f=E%3DE_%7Bred%7D-E_%7Box%5D)
The element wich is reduced is the Fe and the one that oxidates is the Mg:
The electrons transfered (n) in this reaction are 2, so:
b) If you have values of enthalpy and enthropy you can calculate the free-energy by:
with T in Kelvin
Answer:
i would have to add and divide
Explanation:
adding and dividing will get you the answer
first of all there is only two types of selective breeding and they are hybridization and inbreeding.
Ionic bonding would be the answer because they transfer electrons. This gives them a charge. If it loses electrons, it becomes an cation, with a positive charge. While if they gain an electron, they get a negative charge, and become a anion. Transferring an electron is losing or gaining, therefore your answer would be that since electrons are permanently being transferred, the answer is IONIC BOND.
Covalent bonds is a wrong answer because they share electrons, which gives them no charge (neutral).
Also, metallic bonding is not the correct answer.
So our final answer: A- Ionic bond
Number of atom in one mole = 6.022 × 10²³
So, in 3.5 moles, it would be: = 6.022 × 10²³ * 3.5 = 2.1 × 10²⁴
In short, Your Answer would be 2.1 × 10²⁴ atoms
Hope this helps!
