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3 years ago

Compute the average number of units consumed: 504, 519, 576, 321, 256, 101, 76, 75, 127, 289, 367, and 511.

2 answers:

5 0

Add all numbers together = 3722
total of all numbers add together divided by the amount of numbers = 3722 / 12
Answer: 310.16666667

Komok [63]3 years ago

3 0

The answer is about 310.17. Just have to add them all together and than divide by 12.

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27 girls and 18 boys i need same ratio of girls and boys on each team please

otez555 [7]

The ratio is 3:2, hope it helps

7 0

3 years ago

Read 2 more answers

Cv0627

kari74 [83]

Answer:

dr. potter provides 54 vaccinations TOTAL (including both measles and polio).

p+m=54

since there are 4 doses of polio and of measles, you have to use a variable to distinguish how many doses were given for measles and polio out of 142 given doses.

4p+2m=142

p+m=54

4p+2m=142

^^system of equation

p+m=54

4p+2m=142

p=54-m

4p+2m=142

(substitute 54-m to the equation)

4(54-m)+2m=142

m=37

(collect like terms, then substitute the value of m into the first equation)

p=54-37

p=17

(m, p)=(37, 17)

Step-by-step explanation:

i hope this helps, sorry for the wait

5 0

3 years ago

Use the figure below to find the measure of ∠1.

Dmitrij [34]

Answer:

I think it 85 because it looks the same as 4

Step-by-step explanation:

4 0

3 years ago

Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random

lesya692 [45]

Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes $P_B(A)$ .

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
$P(A|B)= \frac{P(A \cap B)}{P(B)}$

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is $\frac{1}{3}$

Part A:
To find the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus $P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}$

P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

Thus $P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$

Therefore, $P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}$

Part B:
To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.

$P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}$

 $P(D)= \frac{1}{3}$ 

Therefore, $P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}$

3 0

3 years ago

Suppose a car has 4 gallons in its tank and the tank holds 14.5 gallons. How long does it take to fill the tank?

SashulF [63]

Answer: 1.75 minutes

Step-by-step explanation:

6 gallons per minute.

14.5-4=10.5

10.5/6=1.75 minutes

3 0

2 years ago