Answer:
y=-1/2x+24
Step-by-step explanation:
you solve for y by isolating the y on one side of the equation and the rest of the equation on the opposite side of the equal sign.
1/2x-1/2x+y=24-1/2x
y=24-1/2x
rewritten: y=-1/2x+24
Answer:
- x = ±√3, and they are actual solutions
- x = 3, but it is an extraneous solution
Step-by-step explanation:
The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...
... x^2(6x -18) = (2x -6)(9)
... 6x^2(x -3) -18(x -3) = 0
...6(x -3)(x^2 -3) = 0
... x = 3, x = ±√3
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Alternatively, you can subtract the right side of the equation and collect terms to get ...
... x^2/(2(x -3)) - 9/(6(x -3)) = 0
... (1/2)(x^2 -3)/(x -3) = 0
Here, the solution will be values of x that make the numerator zero:
... x = ±√3
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So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.
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<em>Comment on the graph</em>
For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.
Answer:
From least to greatest it would be 87, 99, 156, 177
Step-by-step explanation:
The statement "from least to greatest" means starting from the lowest value and transitioning to the greatest value/
Think of it as least -> greatest.
-5/2 is equivalent to -2.5, and if you multiply 2.5 by 2 you get 5, and you have to have the negative, so add that to the 5 and you get -5. Hope this helps!
Answer: The second option and the third option are true.
Step-by-step explanation:
The formula of the line in slope-intercept form is:

Where <em>m </em>is the slope and <em>b </em>is the y-intercept.
By definition, the y-intercept in a direct variation is 0.
Therefore, substituting
and
into the equation, you obtain:

Then, the equation is:

As this is a line, it is a linear function.
Therefore, the second option and the third option are true.