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zaharov [31]
3 years ago
7

identify an equation in point-intercept form for the line parallel to y = -3x + 7 that passes through (2, -4)

Mathematics
1 answer:
Natali5045456 [20]3 years ago
5 0
Let's organize.
The question says to <u>identify</u> an <u>equation in point-intercept form</u> for the <u>line</u> that's <u>parallel</u> to y = -3x + 7 that <u>passes through</u><u /> (2, -4).

If you need to find an equation in point-intercept form that passes through a point, you will substitute the coordinate in this formula:

-> y - yo = m (x - xo)

Where:

(2, -4) -> xo = 2 ; yo = -4
m = Slope

You don't have the slope, but you have the information that the line is <u>parallel</u> to <u />y = -3x + 7. Then you need to know that to a line be <u>parallel to another</u> the Slopes of each other must be equal, mr = ms.

Let's find the slope of the equation given, it is in a slope-intercept form, so:

y = mx + b

R: y = -3x + 7     // I will call this one R line, and the other S.

mr = -3

If the mr = ms, and mr = -3, then the ms = -3 too.

S: y - yo = ms (x - xo) // (2, -4) & ms = -3

-> 
y - (-4) = -3 (x - 2)
-> S: y + 4 = -3 (x - 2) -> This is the point-slope form.


-> 
y = -3x + 6 - 4
-> S: y = -3x - 2 -> This is the slope-intercept form.

I didn't understand what is the point-intercept form that the question requests, but by logic, i think that's the point-slope form.

Answer: The equation in point-intercept form is: y + 4 = -3 (x - 2).
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