A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choo
se "down" as positive and ignore air friction, the
function is h(t) = 16t^2 – 100.
A)t = 2.5 seconds
B)t = 6.25 seconds
C)t = 10 seconds
D)t = 12.5
function is h(t) = 16t^2 – 100.
A)t = 2.5 seconds
B)t = 6.25 seconds
C)t = 10 seconds
D)t = 12.5
1 answer:
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Answer:
Given: The transformation g(x) =6f(x) ......[1]
To find the corresponding values of g(x) for the given transformation.
At x = -7, f(x) = 8
then,
By substituting the value of f(x) = 8 in [1] we have
Similarly,
For x= -3 , f(x) = 3, then
By substituting the value of f(x) = 3 in [1] we have
For x= 0, f(x) = -1 , then
By substituting the value of f(x) = -1 in [1] we have
For x= 2, f(x) = 7, then
By substituting the value of f(x) = 7 in [1] we have
For x= 10, f(x) = 5, then
By substituting the value of f(x) = 5 in [1] we have
Therefore ; we have the corresponding values of g(x) as shown below;
x f(x) g(x)
-7 8 48
-3 3 18
0 -1 -6
2 7 42
10 5 30