A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choo
se "down" as positive and ignore air friction, the
function is h(t) = 16t^2 – 100.
A)t = 2.5 seconds
B)t = 6.25 seconds
C)t = 10 seconds
D)t = 12.5
1 answer:
Answer:
A
Step-by-step explanation:
the rock lands when it reaches height 0.
so, for what t is h(t) = 0 ?
16t² - 100 = 0
16t² = 100
now we pull the square root on both sides (we can ignore the negative solutions, as negative seconds don't make any sense in our scenario)
4t = 10
t = 10/4 = 5/2 = 2.5 seconds
so, A is correct.
You might be interested in
Answer:
50 degrees C
Step-by-step explanation:
5/9(F-32)
5/9=.55555556
(122-32)=90
90×.555555556=50
What's the question being asked here?
It is about 16.9 inches wide
Answer:
I think its c?
Step-by-step explanation:
Im sorry if its wrong.
Answer:
The answer (D)
x=log2(50/3)