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Nadya [2.5K]
2 years ago
11

A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choo

se "down" as positive and ignore air friction, the
function is h(t) = 16t^2 – 100.

A)t = 2.5 seconds

B)t = 6.25 seconds

C)t = 10 seconds

D)t = 12.5

Mathematics
1 answer:
Fiesta28 [93]2 years ago
6 0

Answer:

A

Step-by-step explanation:

the rock lands when it reaches height 0.

so, for what t is h(t) = 0 ?

16t² - 100 = 0

16t² = 100

now we pull the square root on both sides (we can ignore the negative solutions, as negative seconds don't make any sense in our scenario)

4t = 10

t = 10/4 = 5/2 = 2.5 seconds

so, A is correct.

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Please just answer this and explain how to solve...i’m not grasping the work :/
OverLord2011 [107]

\bf Step-by-step~explanation:

We are given that BA is perpendicular to BD, so that must mean that <em>m∠ABD </em>is a right angle, or 90º. This means: (8x - 10) + (4x + 52) = 90º, since both of the angles add up to become a right angle. We have to solve for x in order to find <em>m∠CBD.</em>

<em />

<u>PART 1</u>

<em />

<em />\bf Step~1:<em />

Equation: (8x - 10) + (4x + 52) = 90

Let's add the like values together first.

\bf 8x+4x=12x\\-10+52 = 42

\bf 12x+42=90

\bf Step~2:

Let's subtract 42 from both sides of the equation to isolate the variable we are solving for, x. Our goal is to isolate it completely to get a value that is equal to x.

\bf12x+42(-42)=90(=42)\\12x=48

\bf Step~3:

Divide both sides by 12 to get our final answer for x.

\bf\frac{12x}{12} =x\\\\\frac{48}{12}= 4\\\\x=4

<u>PART 2</u>

<u></u>

Now that we have x, we simply plug it into our equation for <em>m∠CBD. </em>

<em />

<em />\bf Step~1:<em />

\bf4x+52\\4(4)+52

\bf Step~2:

Multiply 4 and add 52.

\bf 4*4=16\\16+52=68

\large\boxed{\bf Our~final~answer: mCBD=68}

8 0
3 years ago
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