Question

Use the quadratic formula to find the zeros. 3x^2=8x+1

Answer 1

Answer:

• x1 = 2.7863
• x2 = - 0.11963

Step-by-step explanation:

Transform the quadratic to

3x^2 - 8x  - 1 = 0

I don't see any obvious factors to this equation so we need to use the quadratic equation.

$\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}$

• a = 3
• b = -8
• c = - 1

$\text{x = }\dfrac{ 8 \pm \sqrt{(-8)^2 - 4*3*(-1) } }{2*3}$

$\text{x = }\dfrac{( 8) \pm \sqrt{64 +12 } }{6}$

$\text{x = }\dfrac{( 8) \pm \sqrt{76 } }{6}$

x = (8 +/- 8.7178 ) / 6

x1 = (16.87178)/6 = 2.7863

x2= (8 -8.7178)/6 = -0.1196