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Vinvika [58]
3 years ago
6

Can someone help me?

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0
I hope this helps you



x.3x+x.(-1)+5.3x+5.(-1)-(x^2-2.4.x+16)


3x^2-x+15x-5-x^2+8x-16


2x^2+22x-21
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The length of a rectangular deck is 4 times it’s width. If the deck’s perimeter is 30ft, what is the deck’s area?
ioda

Try this solution (note, this is not the shortest way):

1. if the given length is 'l' and the width is 'w', then according to the condition 4*l=w;

2. according to the condition the perimeter is 30 ft. Formula of the perimeter is P=2(l+w), then 2(l+w)=30;

3. if to substitute '4*l' instead of 'w', the formula of the perimeter (from item no. 2) will be as 2(4*l+l)=30 or 10*l=30 ⇒ l=3 ft. The length is 3 ft.!

4. if l=3 ft., then w=4*3=12 ft. The width is 12 ft.!

5. Area is

A=w*l; A=12*3=<u>36 ft²</u>

7 0
3 years ago
How do I solve<br> This
Masja [62]

Answer:

v^21 v^3 is the answer by Alena

Step-by-step explanation:


4 0
3 years ago
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The pattern 2, 5, 17, ________, ________ follows the rule multiply by 4, then subtract 3. What are the next two terms?
vitfil [10]

Answer:

None of the answer choices.

Step-by-step explanation:

The pattern to this problem is multiply by 4, and subtract 3. However when doing 17 * 4, you get 68. Look how both of the answer chouces start with 68, and we haven't even subtracted 3 yet. This shows that the answer choices are wrong.

<u>Correct Answer: 65, 257</u>

8 0
2 years ago
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10.1022 rounded to the nearest hundredth​
ivanzaharov [21]

Answer:

10.10

Step-by-step explanation:

4 0
3 years ago
A rectangular swimming pool measures 50 meters in length and 25 meters in width. If the length in the scale drawing is 10 cm, wh
mash [69]

Answer:

The 25 m width of the actual swimming pool in the scale drawing is 5 cm

Step-by-step explanation:

The dimensions of the actual swimming pool given are

Length = 50 meters

Width = 25 meters

The length of the swimming pool on the scale drawing = 10 cm

The scale of the scale drawing is therefore;

10 cm on the scale drawing is equivalent to 50 meters of the actual swimming pool

Which gives;

10 cm:50 m

However, 50 m = 5,000 cm, therefore;

10 cm:5,000 cm or 10 : 5,000

Which is 10 to 5000 or 10/10 to 5000/10 = 1 to 500

The scale of the scale drawing is 1 to 500

or 1 cm of the scale drawing = 5 meters of the actual swimming pool

Therefore, the width of 25 meters of the actual swimming pool can be given as follows;

5 m = 1 cm

1 m = 1 cm/5

25 m = 25× 1 m = 25 × 1 cm/5 = 5 cm

Therefore, the 25 m width of the actual swimming pool in the scale drawing = 5 cm.

5 0
3 years ago
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