All categories

3 years ago

How to simplify the problem

Mathematics

2 answers:

pickupchik [31]3 years ago

7 0

2 to the 5th power I believe.

inysia [295]3 years ago

6 0

I think you would divide each by 2 and get 1 over 1 which would be 1 squared over 1 (negative) cubed

Hope this helps!

You might be interested in

5+4g+8=1 (g=-3;g=-1;g=2)

DochEvi [55]

Hello :
5+4g+8=1
g = -3 : 5+4(-3)+8 = 13-12 = 1 ... right

3 0

3 years ago

And electronics store chain sells headphones The company is about to introduce a new headphones model that is expected to sell v

klasskru [66]

Answer:

$P(x) = -0.25x^2 + 42x - 90$

Step-by-step explanation:

Given

$C(x) = -17x + 90$

$R(x) =- 0.25x^2 + 25x$

Required

Determine the profit function.

Profit function is calculated as thus:

$P(x) = R(x) - C(x)$

So, we have:

$P(x) = -0.25x^2 + 25x -(-17x + 90)$

$P(x) = -0.25x^2 + 25x + 17x - 90$

$P(x) = -0.25x^2 + 42x - 90$

5 0

3 years ago

I am trying to remember how to do Write a two-column proof,

Klio2033 [76]

9514 1404 393

Explanation:

Make use of the properties of equality.

a = 2b +6 . . . . . given

a = 9b -8 . . . . . given

2b +6 = 9b -8 . . . . . . . substitution property of equality

6 = 7b -8 . . . . . . . . . . . subtraction property of equality

14 = 7b . . . . . . . . . . . . . addition property of equality

2 = b . . . . . . . . . . . . . . . division property of equality

b = 2 . . . . . . . . . . . . . . symmetric property of equality

4 0

3 years ago

An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of

ANEK [815]

Answer:

(a) 0.152

(b) 0.789

Step-by-step explanation:

Let's denote the events as follows:

F = The word free occurs in an email

S = The email is spam

V = The email is valid.

The information provided to us are:

The probability of the word free occurring in a spam message is, $P(F|S)=0.60$
The probability of the word free occurring in a valid message is, $P(F|V)=0.04$
The probability of spam messages is,

$P(S)=0.20$

First let's compute the probability of valid messages:

$P (V) = 1 - P(S)\\=1-0.20\\=0.80$

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The probability that a message contains the word free is:

$P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\$

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is spam provided that it contains free is:

$P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\$

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is valid provided that it does not contain free is:

$P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566$

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0

3 years ago

HELP pleaseee..!!!!!!!!!!!!!

GaryK [48]

Answer:

a) 9yd

b) 12ft

Step-by-step explanation:

a) find the square root

b) divide 48 by 4

8 0

3 years ago