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The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.
Further Explanation:
To solve this problem, follow the steps below:
- Write the balanced chemical equation for the given reaction.
- Convert the mass of calcium carbonate into moles.
- Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
- Convert the number of moles of calcium oxide into mass.
Solving the given problem using the steps above:
STEP 1: The balanced chemical equation for the given reaction is:

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.
For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.
Therefore,

Learn More
- Learn more about stoichiometry brainly.com/question/12979299
- Learn more about mole conversion brainly.com/question/12972204
- Learn more about limiting reactants brainly.com/question/12979491
Keywords: thermal decomposition, stoichiometry
Umm where is the question Is this a question ?
Answer:
The new temperature is 894 K or 621 °C
Explanation:
Step 1: Data given
Initial volume of the container = 2.000L
Initial temperature = 25.0 °C = 298 K
Volume increased to 6.00 L
Step 2: Calculate the new temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 2.00L
⇒with T1 = the initial temperature = 25 °C = 298 K
⇒with V2 = the increased volume 6.00 L
⇒with T2 = the new temperature
2.00 L / 298 K = 6.00 L / T2
T2 = 894 K = 621 °C
The new temperature is 894 K or 621 °C