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Alja [10]
3 years ago
8

For each of the following equilibria, write the equilibrium constant expression for Kc. Where appropriate, also write the equili

brium constant expression for Kp.WO3(s)+3H2(g)?W(s)+3H2O(g)
a. Kc=[H2]3[H2O]3
b. Kc=[H2O]3[W][H2]3[WO3]
c. Kc=[H2O]3[H2]3
d. Kc=[H2]3[WO3][H2O]3[W]
Chemistry
2 answers:
valentina_108 [34]3 years ago
6 0

Answer:

option C is the correct answer

c. Kc=[H2O]³/[H2]³

Explanation:

Kp = WO3(s)+3H2(g)?W(s)+3H2O(g)

equilibrium constant expression

 k = \frac{product}{reactant}

=\frac{ [H_20]^3}{H_2]^3}

Solids and liquids are not included in the equilibrium constant expression. This is because they do not affect the reactant amount at equilibrium in the reaction, so they are disregarded and kept at 1

saw5 [17]3 years ago
3 0

Answer:

Answer in explanation

Explanation:

The question asks to write the equilibrium constant expression for the equation. This can be written by placing each of the products in square brackets and raise them to their number of moles, divided by the reactants each raised too, based on number of moles.

The square brackets represent the concentration of the compounds. We write the equilibrium constant expression as follows:

Kc = [H2O]^3[W]/[H2]^3[WO3]

For the equilibrium constant in terms of pressure, we use only the reactants and products that are gaseous.

Kp = [H2O]^3/[H2]^3

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