Answer:
Each oxygen atom is connected to the central O atom with 2 covalent bonds.
Explanation:
Oxygen atoms are connected by two covalent bonds in the oxygen molecule from the Lewis structure, we see that the bond order for O2 is 2 (a double bond) this is clearly seen in the image attached. There are no resonance structures for the oxygen molecule since there are no partial bonds in the molecule, only the two covalent bonds present.
This structure of oxygen shown in the image is its only structure, showing the covalent bonds formed and other non bonding electrons present in the molecule. The octet rule is followed in drawing the structure. Each oxygen atom possesses an octet of electrons on its outermost shell.
<span>The two factors that determine whether or not a molecule is polar are if the individual bonds are even and the </span>shape<span> of the molecule. If the molecule is perfectly symmetric, the molecule will not be polar even if there are polar bonds present.</span>
The answer is; active transport
This means that energy is expended in the process. Because large protein cannot be transported through protein channels in the plasma membrane for being too big, they are transported through endocytosis. This means a vesicle merges with the plasma membrane and forms an invagination that engulfs the protein. The vesicle then encloses with the protein inside and moves into the cell.
Answer:
Br - C ≡ N
Explanation:
To draw the Lewis line-bond structure we need to bear in mind the octet rule, which states that in order to gain stability each <em>atom tends to share electrons until it has 8 electrons in its valence shell</em>.
- C has 4 e⁻ in its valence shell so it will form 4 covalent bonds.
- Br has 7 e⁻ in its valence shell so it will form 1 covalent bond.
- N has 5 e⁻ in its valence shell so it will form 3 covalent bonds.
The most stable structure that respects these premises is:
Br - C ≡ N
It does not have any H atom.
