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Gala2k [10]
3 years ago
5

Glare appears on a computer screen when light from the surroundings reflects off of the screen’s surface. Some computer screens

have a special coating to reduce glare.
Which best explains how the coating works?

A:The coating absorbs light that shines on it and prevents the light from reflecting

B:The surface of the coating is rough, so light that shines on it gets scattered in many directions.

C:The coating bends light that passes through it and prevents the light from reaching the user’s eyes

D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.
Physics
2 answers:
hoa [83]3 years ago
7 0

Answer:

The correct answer is D.

D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.

Explanation:

Glare is produced on a computer screen when light from some external source reflects on the screen.

Anti-glare coating do not absorb light to reduce glare but they actually reduce glare by encouraging the light from the room to pass through the screen so that less light is reflected. Polarized lenses absorbs light to reduce glare, not anti-glare coating.

Basile [38]3 years ago
3 0

Answer: d

Explanation:

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just olya [345]

Answer: Im not entirly sure but I think It's D all the above. I think all but B because I never really heard of that but if you look in our history I think that happen im not sure I would wait untill you know that somone knows for sure.

Explanation:

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2 years ago
Describe J.J Thomson's plum pudding model,and explain how it compares to the modern day atomic theory.​
juin [17]

The correct answer to this open question is the following.

The J.J Thomson's plum pudding model establishes that when he researched the atom, he found that electrons are positively charged. Because he observed that electrons were embedded like plums. Electrons are negative. However, compared to the modern-day atomic theory, scientist Ernest Rutherford established that the space between an atom is empty, the nucleus of the atom is positive, and negative electrons have fixed motion paths.

8 0
2 years ago
Read 2 more answers
In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to
goldenfox [79]

Answer:

17304 J

Explanation:

Complete statement of the question is :

In the winter activity of tubing, riders slide down snow covered slopes while sitting on large inflated rubber tubes. To get to the top of the slope, a rider and his tube, with a total mass of 84 kg , are pulled at a constant speed by a tow rope that maintains a constant tension of 350 N .

Part A

How much thermal energy is created in the slope and the tube during the ascent of a 30-m-high, 120-m-long slope?

Solution :

T = tension force in the tow rope = 350 N

L  = length of the incline surface = 120 m

W_{t}  = work done by tension force = ?

The tension force acts parallel to incline surface, hence work done by tension force is given as

W_{t} = T L\\W_{t} = (350) (120)\\W_{t} = 42000 J

h = height gained by the rider = 30 m

m = total mass of rider and tube = 84 kg

Potential energy gained is given as

U = mgh\\U = (84) (9.8) (30)\\U = 24696 J

Q  = Thermal energy created

Using conservation of energy

Q = W_{t} - U\\Q = 42000 - 24696\\Q = 17304 J

7 0
3 years ago
A crate is placed on an adjustable, incline board. the coefficient of static friction between the crate and the board is 0.29.
sasho [114]

Let the angle be Θ (theta)

Let the mass of the crate be m.

a) When the crate just begins to slip. At that moment the net force will be equal to zero and the static friction will be at the maximum vale.

Normal force (N) = mg CosΘ

μ (coefficient of static friction) = 0.29

Static friction = μN = μmg CosΘ

Now, along the ramp, the equation of net force will be:

mg SinΘ - μmg CosΘ = 0

mg SinΘ = μmg CosΘ

tan Θ = μ

tan Θ = 0.29

Θ = 16.17°

b) Let the acceleration be a.

Coefficient of kinetic friction = μ = 0.26

Now, the equation of net force will be:

mg sinΘ - μ mg CosΘ = ma

a = g SinΘ - μg CosΘ

Plugging the values

a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96

a = 2.7244 - 2.44608

a = 0.278 m/s^2

Hence, the acceleration is 0.278 m/s^2

7 0
3 years ago
The blades in a blender rotate at a rate of 6800 rpm . When the motor is turned off during operation, the blades slow to rest in
tangare [24]
The angular acceleration of the blade when it's switched off is (-6800 rev/min) divided by (2.8 sec) = -2,428.6 rev/(min-sec) = -40.5 rev/sec^2 .
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3 years ago
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