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user100 [1]
2 years ago
7

What was different about the fire Montag saw after leaving the river?

Physics
1 answer:
shtirl [24]2 years ago
3 0

Answer: The answer is A, because before that Montag had only known fire to burn and destroy but now it gives life.

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A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 35 km/h at the 67-m mar
xz_007 [3.2K]

Answer:

0.705 m/s²

Explanation:

a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.

Using newton's law of motion:

v² = u² + 2as

v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h,  s = distance = 67 m

9.72² = 0² + 2a(67)

134a = 94.484

a = 0.705 m/s²

b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:

v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m

v² = u² + 2as

9.72² = 9.72² + 2a(88)

176a = 9.72² - 9.72²

a = 0

c) During the last distance, the speed slows down from 35 km/h to 32 km/h.

u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m

v² = u² + 2as

8.89² = 9.72² + 2a(45)

90a = 8.89² - 9.72²

90a = -15.4463

a = -0.1716 m/s²

The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.

8 0
2 years ago
A ball is dropped from rest on a cliff what is the speed of the ball 5 seconds later
diamong [38]

Answer:

The velocity of the ball after 5 seconds will be 49 m/s

Explanation:

<em>v = final velocity</em>

<em>u = initial velocity</em>

<em>g = acceleration due to gravity</em>

<em>t = time</em>

Initial velocity of the ball = 0 (As the ball is dropped from rest )

Acceleration due to gravity = 9.8 m/s

Time taken = 5 sec

As the acceleration due to gravity is constant in both the cases we can use the equations of motion in order to solve this question

Part I :- As we already know the values of u,g,ant t we can use the first equation of motion in order to find v

Part II :- As we know the values of u, t , g we can use the second equation of motion in order to find s.

Velocity of the ball after 5 seconds

Distance covered by the ball in 5 sec

4 0
2 years ago
The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the c
maria [59]

To solve this problem we will start using the concepts related to the electric field, from there we will find the load exerted on the body. Through this load it will be possible to make a sum of forces in balance to find the load that a human supports. Finally with these values it will be possible to find the repulsive force. We will proceed as follows,

The electric field is

E= \frac{kQ}{R^2}

Here,

k = Coulomb's Constant

Q = Charge

R = Distance (At this case from the center of mass of the earth to the surface)

Rearranging to find the charge,

Q = \frac{ER^2}{k}

Replacing,

Q = frac{(150)(6.38*10^6)}{8.99*10^9}

Q = 6.79*10^5 C

Since the electric field is directed towards the center of earth, the charge is negative.

PART A) Once the load is found we can proceed to apply the balance of Forces, for which the electrostatic force must be equivalent to the weight, this in order to satisfy the balance, therefore

F_w = F_e

mg = \frac{kQq}{R^2}

Replacing,

(62)(9.8) = \frac{(8.99*10^9)(q)(-6.79*10^5)}{(6.38*10^6)^2}

Solving for q,

q = -4.056C

PART B) Finally using the given distance and the values of the found load we can find the repulsive Force, which is

F =\frac{kq^2}{d^2}

F = \frac{(8.99*10^9)(-4.056)^2}{110^2}

F = 1.22*10^7N

PART C) The answer is no. According to the information found, we can conclude that traveling through an electric field is not viable because there is a repulsive force of great magnitude acting on the body.

3 0
3 years ago
Assume your mass is 84 kg. The acceleration due to gravity is 9.8 m/s 2 . How much work against gravity do you do when you climb
KATRIN_1 [288]
M, mass=84 kg
height, h=3.9m
gravity, g= 9.8m/s2
W = F . d
F=force
d=Displacement
W=work done by force
Now by putting the values
F= m g (Acting downward )
d= h (Upward)
W= m g h ( work done against the force)
W= 84•9.8•3.9J
W= 3210.48
Therefore the answer will be 3210.48J.
7 0
2 years ago
Enter the following expression in the answer box below: 2gλ3m−−−−√, where λ is the lowercase Greek letter lambda.
atroni [7]

Answer:

  \sqrt{\dfrac{2g\lambda^3}{m}}

Explanation:

We can write the expression here, but the point of the problem seems to be to see if you can manipulate the controls on the answer box to reproduce that expression.

  \boxed{\sqrt{\dfrac{2g\lambda^3}{m}}}

7 0
3 years ago
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