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4 years ago

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A "gauge 8" jumper cable has a diameter d of 0.326 centimeters. The cable carries a current I of 30.0 amperes. The electric fiel

d E in the cable is 0.062 newtons per coulomb. part a: What electric field E′ would have been required to create a c

1 answer:

Elza [17]4 years ago

3 0

Explanation:

Below is an attachment containing the solution.

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A rubber ball and a steel ball are dropped from the same height onto a concrete floor. They have the same mass, and lets assume

Mkey [24]

Answer:

The average forces would be the same

Explanation:

Both have the same velocity on impact as they fell from the same height.

Both have the same velocity after the bounce because they reach the same height.

Both have the same mass

Both will thus experience the same impulse because both have the same change in momentum.

Therefore both experience the same average force.

5 0

3 years ago

A rifle with a mass of 0.9 kg fires a bullet with a mass of 6.0 g (0.006 kg). The bullet moves with a muzzle velocity of 750 m/s

SCORPION-xisa [38]

Answer:

a ) 4.5 N.s

b) V =5 m/s

Explanation:

given,

mass of rifle(M) = 0.9 kg

mass of bullet(m) = 6 g = 0.006 kg

velocity of the bullet(v) = 750 m/s

a) momentum of bullet = m × v

= 750 × 0.006

= 4.5 N.s

b) recoil velocity

m × u + M × U = m × v + M × V

0 + 0 = 0.006 × 750 - 0.9 × V

V = $\dfrac{4.5}{0.9}$

V =5 m/s

5 0

3 years ago

A trumpet player is tuning his instrument by playing an A note simultaneously with the first-chair trumpeter, who has perfect pi

KIM [24]

To develop this problem, it is necessary to apply the concepts related to Beat

The Beat is an acoustic phenomenon that is generated by two sine waves interfering with slightly different frequencies. The beat frequency is equal to the difference in the frequencies of the two original waves:

$f_{bat} = |(f_1 \pm f_B)|$

Our values are given as

$f_1 = 440Hz$

$f_B = 2.1Hz$

For the particular case we have two possible frequencies:

$1) f_{bat} = |(f_1 - f_B)|$

$f_{bat} = |(440 - 2.1)|$

$f_{bat} = 437.9Hz$

$2) f_{bat} = |(f_B + f_1)|$

$f_{bat} = |(440 +2.1)|$

$f_{bat} = 442.1Hz$

Therefore the two possibles frequencies of the other players note are 437.9Hz and 442.1Hz

4 0

3 years ago

A 20-kg boy slides down a smooth, snow-covered hill on a plastic disk. The hill is at a 10° angle to the horizontal, and the slo

zvonat [6]

Answer:

13 m/s

Explanation:

I assume we are ignoring friction.

The boy's PE will all be converted to KE at the bottom of the hill.

to find PE = mgh we need to know h

h = 50 sin 10 = 8.68 meters

then: PE = 20 * 9.81 * 8.68 =<u> 1703.49</u> j

KE = 1/2 m v^2 = <u>1703 .49</u>

v = 13 m/s

7 0

2 years ago

How are mass and weight different? how does gravity affect mass and weight

m_a_m_a [10]

Mass is the amount of matter in an object whereas weight is the force of gravity acting on the mass of an object. Different planets exert a different force of gravity on an object-meaning that an object's weight will change depending on the force of gravity acting on it, but it's mad will remain unchanged.

8 0

3 years ago