Parallel to y=2x+1 Goes through (5,4)

1 answer:

6 0

      y = mx + b
      y = 2x + 1
y - y₁ = m(x - x₁)
y - 4 = 2(x - 5)
y - 4 = 2(x) - 2(5)
y - 4 = 2x - 10
+ 4     + 4
   y = 2x - 6

You might be interested in

Two circles have the same radius. Is the combined area of the two circles the same as the area of a circle with twice the radius

Dimas [21]

Ok so area=pir^2

2 circles with same area=2pir^2

circle with 2 times radius=pi(2r)^2=pi4r^2=4pir^2

is 2 circles with same area equal to circle with 2 times radius?
is 2pir^2=4pir^2?
is 2=4?
no

therfor the answer is no

it is because the radius is squaered so the doubled gets doubled makng it quadrupuled when the first one only gets doubled

8 0

3 years ago

alaska has land are about 1,700,000 sq kilometers. Florida has a land are 1/10 the size of alaska. what is the land area of Flor

zhannawk [14.2K]

170,000 square kilometers, divide by 10, or take off a 0

8 0

3 years ago

F (n)=3+4 (n-1). find f(5) and f(6)

Rasek [7]

3+16=19,

3+20=23

So the correct answer would be 19 and 23

5 0

3 years ago

Bottles filled by a certain machine are supposed to contain 12 oz of liquid. In fact the fill volume is random with mean 12.01 o

stepan [7]

Answer:

27.43% probability that the mean volume of a random sample of 144 bottles is less than 12 oz.

Step-by-step explanation:

To solve this problem, it is important to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$