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Alchen [17]
2 years ago
12

63 decreased by twice Vidya's height

Mathematics
1 answer:
galben [10]2 years ago
4 0
Vidya's height=x
because decreased means subtraction (-) and twice means times 2
it should be 63-2x
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What is the basic ratio for 25:40.
Alexxandr [17]
25/40= .625
.625= 5/8
8 0
3 years ago
H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
zubka84 [21]
H(x)=(x^2)+1\ \ \ \ and\ \ \ \  K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.
4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B400%20%5Ctimes%20400%20-%2024%20%5Ctimes%20400%20-%20360%20%5Ctimes%20400%20-%202
max2010maxim [7]

Answer:

\sqrt{400 \times 400 - 24 \times 400 - 360 \times 400 - 200} \\  \\  = \sqrt{160000 - 9600 - 144000 - 200} \\  \\  = \sqrt{160000 - 9600 - 144000 - 200} \\  \\ = \sqrt{160000 - 153,800} \\  \\  = \sqrt{6200} \\  \\  = 78.74 \\  \\

7 0
3 years ago
The sum of two consecutive even numbers is 210.
WITCHER [35]

Answer:

104, 106

Step-by-step explanation:

Hello!

A consecutive number is a number that comes after the other.

Let the first even integer be x. Since there is an even integer for every two integers, the second number should be x + 2.

<h3>Solve for x</h3>
  • (x) + (x + 2) = 210
  • x + x + 2 = 210
  • 2x + 2 = 210
  • 2x = 208
  • x = 104

The second number is x + 2, so it would be 106.

6 0
1 year ago
Read 2 more answers
Quincy is building a tower out of blocks that are each 5/6 of an inch in height. He decides
adoni [48]

Answer:

90 inches tall

Step-by-step explanation:

5/6 of 12 is 10 so the blocks are 10 inches tall each 10x9 is 90

5 0
2 years ago
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