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Serga [27]
3 years ago
14

Light waves come in many different varieties, and can be seen as many different colors. What is the main difference between a li

ght wave that produces the color blue, and a light wave that produces the color red?
Chemistry
2 answers:
NARA [144]3 years ago
8 0

Answer:

The wavelength

Explanation:

Each wavelength is perceived by our eyes as a different color. The shorter wavelengths of visible light are violet — we might call them purple. ... For example, insects can see ultraviolet waves — waves just before purple on the electromagnetic spectrum.

VMariaS [17]3 years ago
5 0
The difference is the wavelength of the light waves.
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timama [110]

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4 0
3 years ago
Read 2 more answers
Question 1(Multiple Choice Worth 3 points)
Bingel [31]

1) Answer:

moles of oxygen (n) = 1.86 moles

Explanation:

according to  Boyle's law the formula to solve this problem is:

PV=nRt

when P is the pressure which equal 1.25 atm

and V is the volume which equal 37.5 L

n is the number of moles which we need to calculate it

R is constant which equal 0.082

t is the temperature in kelvin

By substitution:

1.25*37.5 = n * 0.082 * 307

So n = 1.86 moles

2) Answer:

the volume of oxygen gas = 34 L

Explanation:

at standard temperature and pressure (STP) 1 mole of gas will equal = 22.4L

So when we have 1.5 moles of oxygen at standard temperature and pressure (STP) so we will estimate it like that

1.5 moles *22.4 L/ 1 mole = approximately 34 L

3) Answer:

The volume of H2 = 2.29 L

Explanation:

according to the Balanced equation we can see that the molar ratio between Zn and H2 1 : 1

so to know the number of moles of H2 we will get it for Zn first :

number of moles Zn = mass of Zn / molar mass Zn

                             = 5.98 / 65.39 =0.0914 moles

so number of moles H2 = 0.09 moles

by  substitution in the following formula:

PV = nRT

0.978 * V = 0.09 * 0.082 * 298

so The volume of H2 = 2.29 L

4) Answer:

Volume of O2 = 1.4 L

Explanation:

first we have to balance  the equation:

2Na2O2 +2CO2 → 2Na2CO3 + O2

2 mole CO2 give 1 mole of O2 so the molar ratio is 2:1

at STP 1 mole of gas will equal = 22.4 L

             ??? moles of CO2 = 2.8

n CO2 = 0.125 moles so n O2 = 0.125 /2 = 0.0625 moles

so when 1 mole of as = 22.4

              0.0625 moles O2 = ???

Volume of O2 =0.0625 moles * 22.4 L/ 1 mole

                        = 1.4 L

5) Answer:

the initial quantity of sodium metal used = 17.2 gram

Explanation:

at STP 1 mole of gas will equal = 22.4 L

so  moles of H2 equal ?? when 8.40 liters of H2 gas were produced

so moles of H2  = 8.4/22.4 =0.375 moles

and according to the balanced equation the molar ratio between H2 ans Na is 1 : 2

so number of moles for Na = 0.375 *2 = 0.75 moles

to get the initial quantity of sodium metal (mass Na) = number of moles * molar mass

mass Na = 0.75 moles * 23 gm/mole= 17.25

6) Answer:

False

Explanation:

because STP means standard temperature and pressure. and the Standard temperature must be 273 K and the standard pressure must be 1 atm but in the question the temperature is 298 K not 273 K so , It is not a standard temperature

7) Answer:

22.4 liters

Explanation:

1 mole of gas will equal = 22.4 L

because at the Standard temperature must be 273 K and the standard pressure must be 1 atm

so V = nRT/P

       =1 mole * 0.082 * 273 K / 1 aTm

        = 22.4 liters

4 0
4 years ago
What is the ph of with a 4.6 x 10-6 M hydroxide ion concentration?
nlexa [21]
<h3>Answer:</h3>

pH = 8.66

<h3>Explanation:</h3>
  • The pH refers to the acidity or alkalinity of a solution.
  • It is calculated by getting the negative logarithm of Hydrogen ions concentration.
  • pH=-log[H⁺]

In this case;

we are given [OH⁻] as 4.6 x 10^-6 M

We are required to calculate the pH

We need to know that;

pH + pOH = 14

pOH = -log[OH⁻]

To get the pH we can calculate the pOH first,

pOH = -log[4.6 x 10^-6 M]

        = 5.34

but, pH + pOH = 14

Therefore, pH = 14 - pOH

                        = 14 - 5.34

                        = 8.66

Therefore, the pH of the solution is 8.66

3 0
3 years ago
If the half life of a radioactive isotope is 1 day, then how much of the original isotope remains at the end of two days?
ikadub [295]

\huge{\color{magenta}{\fcolorbox{magenta}{black}{\huge{\color{white}{\fcolorbox{aqua}{black}{✿ᴀɴsᴡᴇʀ✿}}}}}}

25%

Explanation:

In a half life of a radioactive isotope is 1 day,it means it loses its half mass each day

We a formula for N half life

\sf  { \frac{1}{2} }^{n}

where n is the number of days

Here the isotope is kept for 2 days

so it's left over mass will be

\sf { (\frac{1}{2}) }^{2}  \\  \\  \\  \frac{1}{2}  \times  \frac{1}{2}  \\  \\  \sf  \frac{1}{4}

It's left over mass 1/4th of the original mass

Now, we need to find it's percentage by multiplying with 100

\sf  \frac{1}{4}  \times 100 \%\\  \\  \sf   \cancel\frac{100}{4} \% \\  \\  \sf 25\%

<u>So</u><u> </u><u>2</u><u>5</u><u>%</u><u> </u><u>mass</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>2</u><u> </u><u>day</u><u> </u><u>of</u><u> </u><u>half</u><u> </u><u>life</u><u> </u><u>radioactive</u><u> </u><u>isotope</u><u>.</u><u> </u>

8 0
2 years ago
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Which of the following pair has a larger size? a)K or K- b)Br or Br- c)O2- or F- d) Li or Na​
Anna11 [10]

Answer:

jabvVbbnndbznnsnsksloplshebxbsnejxjevdjdjwjsjxbsjwpzbrjsjdndn

Explanation:

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3 years ago
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