One airplane is 78 miles due south of a control tower. Another airplane is 52 miles from the control tower at a heading of N 38 degrees E. To the nearest tenth of a mile, how far apart are the two airplanes?
1 answer:
Answer:
123.2 miles
Step-by-step explanation:
Given that One airplane is 78 miles due south of a control tower. Another airplane is 52 miles from the control tower at a heading of N 38 degrees E. To the nearest tenth of a mile, how far apart are the two airplanes?
The angle Ø = 90 + 52 = 142 degree
Or 180 - 28 = 142 degree
Using cosine formula
D^2 = 78^2 + 52^2 - 2(78)(52)Cos142
D^2 = 6084 + 2704 - 8112Cos142
D^2 = 8788 + 6392.34
D^2 = 15180.34
D = 123.2 miles
Therefore, the two planes are 123.2 miles apart.
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