.108 I hope that this helps
Answer:
y = -1/4
Step-by-step explanation:
y/5 +3/10 = (y+2)/7
The LCD is 10·7 = 70. Multiplying the equation by 70 gives ...
14y +21 = 10(y +2)
14y +21 = 10y +20 . . . . eliminate parentheses
4y + 21 = 20 . . . . subtract 10y
4y = -1 . . . . . . . . . subtract 21
y = -1/4 . . . . . . . . .divide by 4
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<em>Check</em>
(-1/4)/5 +3/10 = (-1/4 +2)/7 . . . . . substitute for y
-1/20 +6/20 = (7/4)/7 . . . simplify a bit, rewrite 3/10
5/20 = 1/4 . . . . . . . . . . true
A Rubik's cube is, well, a cube.
That means that each if its faces is a square, a quadrilateral with four right angles and four sides if the same length.
If the length of one side is x,
4x=22.2
x=5.55 centimeters.
Hope this helps!
Your fortune is "All your hard work will finally pay off."
(credits to
trombonebookworm)
This is a model of 63÷6. :)
Label the 3 distinct sides of the box. I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:
ab=54 in^2
ac=90 in^2
bc=60 in^2
Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c. Then the volume of the box is a*b*c.
Example: bc = 90, but c = 60/b. You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.
Continuing this procedure, I determined that a=9, b=6 and c=10. Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)
