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3 years ago

When given a quadratic equation, how do I graph it, and find the vertex?

1 answer:

4 0

So let’s say the equation is x^2 (x squared) -4x + 8 = 0. So you have to eventually graph a palabara. So to get the vertex, you have to find the line of symmetry (this plays a big part). So the formula for the line of symmetry is x= -b/2a. So A is this equation is 1. B is -4. C is 8. So you would plug these numbers in and you get 2. So (2,0) is your like of symmetry. Now you have to plug 2 back in for x. So when you do that you get 4 so the vertex is (2,4). So the vertex is (2, 4) and basically what the vertex is is it is the highest or lowest point of a palabara. So you can tel if it opens up or down by looking is A is negative or positive. If A is negative the it opens down. If it is positive then it opens up. So now you just put points in. Create a t chart. Like x/y. So when X is 1 for example, y is 5. So you graph (1, 5) and you graph the point that is the same distance from the line of symmetry. You do this until you have 5 points. I hope this helps. It’s hard to teach this over text.

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Help Sjsjjjsjajajahjajaja

motikmotik

Answer:

Step-by-step explanation:

${5}^{2} + {x}^{2} = {7}^{2} \\ 25 + {x}^{2} = 49 \\ {x}^{2} = 49 - 25 \\ {x}^{2} = 24 \\ x = \sqrt{24}$

have a nice day

6 0

2 years ago

A line passes through the points (-4, -3) and (2,6). Determine the slope of the line

Grace [21]

Slope is 1/2. The equation to solve it is y2-y1 / x2-x1. I hope you understand it now :)

4 0

3 years ago

Read 2 more answers

NO LINKS!!! PLS HELP ME IM TRYING TO GRADUATE PLSSS !!! Find the midpoint of the segment below and enter its coordinates as an

Leto [7]

Answer:

x = 5/2 , y = -7/2

Step-by-step explanation:

r's your solution

=> formula for finding midpoint =.( X1 + X2/)/2 , (Y1+Y2)/2

=> putting the value of in formula

=> x= 4+1/2 , y = -1-6/2

=> x = 5/2 , y = -7/2

hope it helps

3 0

3 years ago

General solutions of sin(x-90)+cos(x+270)=-1 {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

4 0

3 years ago

samanthas house is 72 feet wife. in a photograph the width of the house was 4 inches, and its height was 2.5 inches. what is the

Anna11 [10]

So to find the ratio of the actual house to the house in the picture you would divide 72/4 to get 18. this means that the ratio is 18:1. Now multiply 2.5 x18 to get the real life height of the house. 2.5x18=45.
So the house is 45 feet tall.
Please anyone correct me if I'm wrong but I think this is right.

7 0

2 years ago