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GaryK [48]
3 years ago
14

Solve this equation please ! −2 − (+7) = ?

Mathematics
1 answer:
olga55 [171]3 years ago
5 0
-2 - (+7) =
-2 - 7 =
-9
<3
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On the playground the teacher observed bicycles and tricycles. she counted 72 wheels and 28 total cycles. How many of them were
Andreyy89

Answer:

  16 tricycles

  12 bicycles

Step-by-step explanation:

If all were bicycles, there would be 28·2 = 56 wheels. Each additional wheel indicates the presence of a tricycle instead of a bicycle.

There are 72 -56 = 16 tricycles. The remaining 28-16 = 12 are bicycles.

3 0
3 years ago
Question 3(Multiple Choice Worth 5 points) (06.08A) Simplify negative 15.5 divided by 5 .. −3.1 3.1 −3.3 3.3
xz_007 [3.2K]

A negative divided by a positive gives a negative result

So the answer is -3.1

Hope this helps!

3 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the points
zubka84 [21]

Answer <u>(assuming it can be in slope-intercept form): </u>

y = x - 5

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula, m = \frac{y_2-y_1}{x_2-x_1}, and substitute the x and y values of the given points into it. Then, solve:

m = \frac{(2)-(1)}{(7)-(6)} \\m = \frac{2-1}{7-6} \\m = \frac{1}{1} \\m = 1

2) Now that we know the slope and at least one point the line crosses through, we can write an equation of the line in point-slope form, or y-y_1 = m (x-x_1). Substitute m, x_1, and y_1 for real values.

Since m represents the slope, substitute 1 for it. Since x_1 and y_1 represent the x and y values of a point the line intersects, use any one of the given points (either one is fine, either way the equation will represent the same line) and substitute its x and y values into the equation. (I chose the point (6, 1), as seen below.) Finally, isolate y to put the equation in slope-intercept form.

y-1 = 1(x-6)\\y -1 = x-6\\y = x -5

6 0
3 years ago
Use elimination to find the value of x in the solution for the system of equations. 2x+2y=10,2x-3y=5
jeyben [28]
Elimination

2x+2y=10
2x-3y=5
multiply first equatn by -1

-2x-2y=-10
add to second equation

2x-3y=5
<u>-2x-2y=-10  +
</u>0x-5y=-5
-5y=-5
divide both sides by 5
-y=-1
muitply b-1
y=1

subsitue
2x+2y=10
2x+2(1)=10
2x+2=10
subtract 2
2x=8
divide  2

x=4


x=4
y=1
solution in (x,y) form is
(4,1)
<u />
5 0
3 years ago
In ∆ABC, if sin A = 4/5 and tan A = 4/3 , then what is cos A?
Alexxandr [17]

Answer:

A = 3/5

Step-by-step explanation:

At the outset, the question doesn't give us a figure to refer to nor does it tell us if this is a right angled triangle. However we observe that both sin A and tan A have the numbers 3, 4 and 5. We recognize this to be consistent with  3-4-5 standard right angled triangle.

Hence we can guess that it is probably a right angled triangle, but we should do the following to confirm:

Knowning that for a right angled triangle,

sin A = opposite / hypotenuse = 4/5

tan A = opposite / adjacent = 4/3

From this we can surmise that

Opposite = 4

hypotenuse = 5

adjacent = 3

Assemble the triangle to see if this works (see attached). We can futher verify that 3-4-5 works using the Pythagorean theorem.

Now that we have determined that the triangle is a 3-4-5 right angled triangle,

cos A = adjacent / hypotenuse = 3/5

8 0
3 years ago
Read 2 more answers
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