<em><u>Question:</u></em>
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
<em><u>Answer:</u></em>
The vertical asymptotes are x = 2 or x = -1
<em><u>Solution:</u></em>
Given that,

For vertical asymptotes, set the denominator to zero and then solve the quadratic equation


Thus the vertical asymptotes are x = - 1 and x = 2
To find 15% of 130=
130 x 0.15=
19.5
The answer is false. The radius is half the diameter, not 2 times it.
Answer:
36
Step-by-step explanation:
angle ACB = 180-130=50 degree
angle ABC = 180 - (94+50)
= 180-144
= 36

has gradient

which at the point (-1, 4, 3) has a value of

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say
, in which case we have

Then the derivative of
at (-1, 4, 3) in the direction of
is
