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Marrrta [24]
3 years ago
7

How much more mass does 12Mg have than 12g

Physics
1 answer:
Masja [62]3 years ago
4 0

Explanation:

Given that,

First mass, m_1=12\ Mg

Other mass, m_2=12\ g

We know that,

1 Megagram (Mg) = 10⁶ grams (g)

So, 1\ g=10^{-6}\ Mg

Using unitary method,

m_2=12\ g=12\times 10^{-6}\ Mg    

So, m_1-m_2=12\ Mg-12\times 10^{-6}\ Mg

m_1-m_2=10^{-6}

So, the mass of 12 Mg is 10^{-6} more than 12 grams. Hence, this is the required solution.                          

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Which of the following statements are true of an object in orbit around Earth? (Select all that apply.) The gravity force on the
faltersainse [42]

Answer:

All these statement are true

Explanation:

Gravity will be acting like a centripetal force for the circular motion of object around earth, which makes it perpendicular to the velocity vector. In the case of elliptical motion, gravity can still be divided into 2 vectors, one parallel and the other perpendicular to the velocity. At the nearest point in elliptical motion, gravity is directly perpendicular to velocity just like in circular motion. At the farthest point, the potential energy is minimized and has been converted into kinetic energy. Therefore at this point the speed is greatest.

5 0
4 years ago
A small ball of charge Q and mass m has a velocity v at infinity. It collides head-on with a ball of the same charge and mass wh
Hatshy [7]

Answer:

Explanation:

Kinetic energy of ball in motion = 1/2 m v² . Potential energy = 0

Let the minimum distance between the balls be d  on collision.

Electric potential energy at that time= k Q²/d , Here kinetic energy is converted into potential energy . So

1/2 m v² = kQ²/d

d =2 k Q² / mv²,= 18 x 10⁹ x Q²/ m v².

8 0
4 years ago
How is the strength of an electromagnet affected by the number of turns<br> of wire in a coil?<br> e
Anastasy [175]

Answer:I don't know

Explanation:

3 0
3 years ago
A coil of 10 turns is in the shape of an ellipse having a major axis of 13.0 cm and a minor axis of 6.00 cm. The coil rotates at
bearhunter [10]

Answer:

the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V

Explanation:

Given the data in the question;

Number of turns N = 10

major axis Ma = 13 cm = 0.13 m

a = 0.13/2 = 0.065 m

Minor axis Mi = 6 cm = 0.06 m

b = 0.06/2 = 0.03 m

we know that; 1 RPM = 0.10472 rad/s

rate of rotation R = 73rpm = 7.64 rad/s

Magnetic field = 55 uT

we know that, Area of ellipse = π × a × b

we substitute

A = π × 0.065 m × 0.03 m

A = 0.006126 m²

so

Maximum Voltage = N × Area × Magnetic field × rate of reaction

we substitute

Maximum Voltage = 10 × 0.006126 × ( 55 × 10⁻⁶ ) × 7.64

Maximum Voltage = 2.574 × 10⁻⁵ V

Therefore, the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V

6 0
3 years ago
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
frutty [35]

Answer:

Velocity=1.1m/s

Amplitude=0.35m

Explanation:

Given:

time 't' = 2.9s

wavelength 'λ'= 5.5m

distance 'd'=0.7m

The time period 't' is the time b/w two successive waves. Therefore, the time it takes from the boat to travel  from its highest point to its lowest is a half period.

So, T = 2 x 2.9 => 5.8 s

As we know that frequency is the reciprocal of time period, we have

f= 1/T = 1/5.8 =>0.2 Hz

In order to find how fast are the waves traveling, the velocity is given by

Velocity = f λ

V= 0.2 x 5.5 =>1.1m/s

The distance between the boat's highest point to its lowest point is double the amplitude.

Therefore , we can write

Amplitude 'A'= d/2 =>0.7/2 =>0.35m

8 0
3 years ago
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