Question

How much more mass does 12Mg have than 12g

Answer 1

Explanation:

Given that,

First mass, $m_1=12\ Mg$

Other mass, $m_2=12\ g$

We know that,

1 Megagram (Mg) = 10⁶ grams (g)

So, $1\ g=10^{-6}\ Mg$

Using unitary method,

$m_2=12\ g=12\times 10^{-6}\ Mg$    

So, $m_1-m_2=12\ Mg-12\times 10^{-6}\ Mg$

$m_1-m_2=10^{-6}$

So, the mass of 12 Mg is $10^{-6}$ more than 12 grams. Hence, this is the required solution.