Answer:
the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V
Explanation:
Given the data in the question;
Number of turns N = 10
major axis Ma = 13 cm = 0.13 m
a = 0.13/2 = 0.065 m
Minor axis Mi = 6 cm = 0.06 m
b = 0.06/2 = 0.03 m
we know that; 1 RPM = 0.10472 rad/s
rate of rotation R = 73rpm = 7.64 rad/s
Magnetic field = 55 uT
we know that, Area of ellipse = π × a × b
we substitute
A = π × 0.065 m × 0.03 m
A = 0.006126 m²
so
Maximum Voltage = N × Area × Magnetic field × rate of reaction
we substitute
Maximum Voltage = 10 × 0.006126 × ( 55 × 10⁻⁶ ) × 7.64
Maximum Voltage = 2.574 × 10⁻⁵ V
Therefore, the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V
