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4 years ago

Which statement justifies that phosphine (PH3) is a polar molecule?

1 answer:

4 0

The P-H bond is polar and the molecule is asymmetric.

Non-polar bonds cannot produce polar molecules and symmetric bonds result in even distribution of charge, so no net charge is observed.

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What happens to the ammonia and hydrogen gases generated in common zinc carbon dry cell..?

Anna [14]

Answer:

A zinc- carbon battery dry cell primary that delivers about 1.5 volts of direct current.

Explanation:

hydrogen gas escapes while retaining the aqueous electrotype.

4 0

3 years ago

For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl₂):(b) Assuming that ΔS° and ΔH° change little wi

maksim [4K]

ΔG° at 450. K is -198.86kJ/mol

The following is the relationship between ΔG°, ΔH, and ΔS°:

ΔH-T ΔS = ΔG

where ΔG represents the common Gibbs free energy.

the enthalpy change, ΔH

The temperature in kelvin is T.

Entropy change is ΔS.

ΔG° = -206 kJ/mol

ΔH° equals -220 kJ/mol

T = 298 K

Using the formula, we obtain:

-220kJ/mol -T ΔS° = -206kJ/mol

220 kJ/mol +206 kJ/mol =T ΔS°.

-T ΔS = 14 kJ/mol

for ΔS-14/298

ΔS=0.047 kJ/mol.K

450K for the temperature Completing a formula with values

ΔG° = (450K)(-0.047kJ/mol)-220kJ/mol

ΔG° = -220 kJ/mol + 21.14 kJ/mol.

ΔG°=198.86 kJ/mol

Learn more about ΔG° here:

brainly.com/question/17214066

#SPJ4

7 0

2 years ago

devlian [24]

Answer:

The final temperature of both substances at thermal equilibrium is 17.3°C

Explanation:

To calculate the final temperature of both substances at thermal equilibrium -:

First , we calculate the heat of A1 cube as follows -

q= mSΔT

(where q = heat of the cube , m = mass of cube , S= specific heat of cube {0.902j/g°C}, T = Temperature )

Putting the values given in the question ,

$q= 32.5g\times0.902\j/g$ ° $C$ $\times(T_f-45.8$ ° $C)$

$29.315\times(T_f-45.8)J$

Now , calculate the heat of water -

q=mSΔT

Putting values from the question ,

$q=105.3g\times4.18j/g$ ° $C$ $\times (T_f-15.4$ ° $C)$

= $440.154\times(T_f-15.4)J$

Now ,

Heat lost by water A1= Heat gained by water [negative sign about heat lost]

$-29.315\times(T_f-45.8)J$ $=440.154\times(T_f-15.4)J$

$\frac{-(T_f-45.8)J}{T_f-15.4)J} =\frac{440.154}{29.315}=15.0$

$-T_f+45.8$ ° $C=15T_f-231.2$ ° $C$

$(45.8+231.2)$ ° $C$ = $16T_f$

$16T_f=277.03$ ° $C$

$T_f=\frac{277.03}{16}$ = 17.3°C

Therefore , the final temperature of both substances at thermal equilibrium is 17.3°C

3 0

3 years ago

What substance is most likely the most dense chlorine,oxygen,bromine, and silver

Reil [10]

Silver is the densest as it is lower on the periodic table containing more protons and nuetrons and electrons

7 0

3 years ago

Read 2 more answers

Answer #4 and #5 make sure you have proof and will give brainliest

sweet-ann [11.9K]

Answer:

B,C

Explanation:

7 0

3 years ago

Read 2 more answers