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3 years ago

Celina has a water sample that’s contaminated with salt and microorganisms. Which method should she use to purify the water?

Chemistry

2 answers:

kap26 [50]3 years ago

7 0

Answer: Second option is correct.

Explanation:

Filtration is the method of removing impurities solid particles from liquid.

Distillation is the method of removing impurities in a boiling liquid mixture.

Osmosis is the movement of water from low concentration to high concentration through a plasma membrane.

Reverse osmosis is the method of purification of water to remove ions and unnecessary molecules from drinking water.

We have given the situation that "There is a water sample contaminated with salt and micro organisms."

We need to purify the water.

Filtration is the best method to purify the water and remove the salt and micro organisms.

As there is slight difference between filtration and distillation.

In distillation we need to boil the water , so there heat is needed for this whereas in filtration, it just remove solid from fluid without being heated.

Hence, Second option is correct.

Alik [6]3 years ago

3 0

B) filtration
(hope this helps) ~A

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3 years ago

A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat

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Answer:

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B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

$C=I\times t$

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

$\text{Moles of electrons}=\frac{C}{F}$

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

$Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)$

I = 0.790 A, t = 30.0 min = 1800 seconds

$C=I\times t$

$C=0.790 A\times 1800 s=1422 C$

Moles of electron transferred:

$=\frac{1422 C}{96500 F}=0.01474 mol$

Now, to calculate the moles of gallium, we use the equation:

$\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}$

n = number of electrons transferred = 3

$\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol$

Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g

B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

$Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$

Moles of tin = $\frac{8.70 g}{119 g/mol}=0.07311 mol$

n = number of electrons transferred = 2

$\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}$

Moles of electron = $n\times \text{Moles of tin}$

$=2\times 0.07311 mol=0.14622 mol$

Charge transferred during time t :

$\text{Moles of electrons}=\frac{C}{F}$

$C=96500 F\times 0.14622 mol=14,110.23 C$

Current applied for t time = I = 5.79 A

$t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs$

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

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Answer:

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3 years ago

Read 2 more answers

Calculate the pH at of a 0.10 Msolution of anilinium chloride . Note that aniline is a weak base with a of . Round your answer t

notsponge [240]

The question is incomplete, here is the complete question:

Calculate the pH at of a 0.10 M solution of anilinium chloride $(C_6H_5NH_3Cl)$ . Note that aniline $(C6H5NH2)$ is a weak base with a $pK_b$ of 4.87. Round your answer to 1 decimal place.

<u>Answer:</u> The pH of the solution is 5.1

<u>Explanation:</u>

Anilinium chloride is the salt formed by the combination of a weak base (aniline) and a strong acid (HCl).

To calculate the pH of the solution, we use the equation:

$pH=7-\frac{1}{2}[pK_b+\log C]$

where,

$pK_b$ = negative logarithm of weak base which is aniline = 4.87

C = concentration of the salt = 0.10 M

Putting values in above equation, we get:

$pH=7-\frac{1}{2}[4.87+\log (0.10)]\\\\pH=5.06=5.1$

Hence, the pH of the solution is 5.1

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