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Assoli18 [71]
3 years ago
5

in 1912, chemist fritz haber developed a process that combined nitrogen from the air with hydrogen at high temperatures and pres

sures to make ammonia. specifically, the process involved combining one molecule of nitrogen gas (n2) with three molecules of hydrogen gas (h2) to get two molecules of ammonia (nh3). if you write this process in a symbol format, it looks like this:n2 3h2 → 2nh3explain whether this is a chemical or physical change, and why. does it involve elements, compounds, mixtures, or pure substances? also describe how many atoms are involved before and after. what do you notice about the number of atoms?
Chemistry
1 answer:
Virty [35]3 years ago
3 0
Explain whether this is a chemical or physical change, and why. does it involve elements, compounds, mixtures, or pure substances?

If the process involves a chemical reaction then surely it is a chemical change where new bonds are being formed from the collision of the reactants.

Describe how many atoms are involved before and after. what do you notice about the number of atoms?

From the balanced chemical reaction, we see that we need 1 mol of N2 gas and 3 mol of H2 in order to form 2 mol of NH3.
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Consider the reaction:
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Answer:

\large \boxed{\text{-851.4 kJ/mol}}

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                            2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹:         0         -824.3         -1675.7         0

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

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