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Assoli18 [71]
2 years ago
5

in 1912, chemist fritz haber developed a process that combined nitrogen from the air with hydrogen at high temperatures and pres

sures to make ammonia. specifically, the process involved combining one molecule of nitrogen gas (n2) with three molecules of hydrogen gas (h2) to get two molecules of ammonia (nh3). if you write this process in a symbol format, it looks like this:n2 3h2 → 2nh3explain whether this is a chemical or physical change, and why. does it involve elements, compounds, mixtures, or pure substances? also describe how many atoms are involved before and after. what do you notice about the number of atoms?
Chemistry
1 answer:
Virty [35]2 years ago
3 0
Explain whether this is a chemical or physical change, and why. does it involve elements, compounds, mixtures, or pure substances?

If the process involves a chemical reaction then surely it is a chemical change where new bonds are being formed from the collision of the reactants.

Describe how many atoms are involved before and after. what do you notice about the number of atoms?

From the balanced chemical reaction, we see that we need 1 mol of N2 gas and 3 mol of H2 in order to form 2 mol of NH3.
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How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
EDTA EDTA is a hexaprotic system with the p K a pKa values: p K a1 = 0.00 pKa1=0.00 , p K a2 = 1.50 pKa2=1.50 , p K a3 = 2.00 pK
mihalych1998 [28]

Answer:

Check the explanation

Explanation:

When,

pH = -log[H+] = 3.30

[H+] = 5.0 X 10^{-4} M

Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^{-11}

alpha[Y^-4] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6

= 1.56 X 10^{-20} + 3.12 X 10^{-17} + 2 X 10^{-15} + 4 X 10^{-14} + 1.6 X 10^{-13} + 2.34 X 10^{-16} + 2 X 10^{-23}

= 2.02 X 10^{-13}

When,

pH = -log[H+] = 10.15

[H+] = 7.08 X 10^{-11} M

Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^-11

alpha[Y^{-4}] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6

= 1.26 X 10^{-61} + 1.8 X 10^{-51} + 8.1 X 10^{-43} + 1.12 X 10^{-34} + 3.17 X 10^{-27} + 3.3 X 10^{-23} + 1.83 X 10^{-23}

= 5.12 X 10^{-23}

4 0
3 years ago
How many hydrogen atoms are in 5.20 mol of ammonium sulfide?
Fofino [41]
1) Molecular formula of ammonium sulfide

(NH4)2 S

2) That means that there are 2*4 = 8 atoms of hydrogen in each molecule of ammoium sulfide, so in 5.20 mol of molecules will be 8 * 5.20 mol = 41.6 moles of atoms of hydrogen

3) To pass to number of atoms multiply by Avogadro's number: 6.022 * 10^23

41.6 moles * 6.022 * 10^23 atoms / mol = 250.5 * 10^23 = 2.50 * 10^25 atoms

Answer: 2.50 * 10^25
8 0
3 years ago
Why is it important to monitor pH levels in natural bodies of water?
AleksandrR [38]

Answer:

Since pH can be affected by chemicals in the water, pH is an important indicator of water that is changing chemically

Explanation:

pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water. Water that has more free hydrogen ions is acidic, whereas water that has more free hydroxyl ions is basic

3 0
3 years ago
Read 2 more answers
What mass of sucrose needs to be dissolved in 540 g of water in order to prepare a 15% by mass solution.
Lilit [14]

Answer:

95.3g

Explanation:

Given parameters:

Mass of water  = 540g

Percentage by mass of solution = 15%

Unknown:

Mass of sucrose = ?

Solution;

To solve this problem, we must understand that a solution is made up of solute dissolved in a solvent. A solute is the solid dissolved in another. The solvent is the is dissolving medium;

    Percentage by mass of solute in solution = \frac{Mass of solute}{Mass of solution}  x 100

Mass of solution  = mass of water + Mass of sucrose  = 540 + M

  where M is the mass of sucrose;

therefore;

                 \frac{M}{540 + M }  x 100   = 15

   Solving for M gives 95.3g

Mass of sucrose is 95.3g

5 0
3 years ago
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