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3 years ago

Liquid helium boils at –268.93 °C. What is the boiling point of helium on the Kelvin temperature scale?

Chemistry

2 answers:

____ [38]3 years ago

7 0

Answer:

-268.93+273=4.07K

Explanation: When solving for Kelvin you want to add 273 which is the constant to get your answer which should be 4.07K.

BARSIC [14]3 years ago

4 0

In order to change celcius to kelvin always add 73 to it leaving you with -195.93

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if the reduced row echelon form of the augmented matrix for a linear system has a row of zeros, then the system must have infini

BigorU [14]

Answer:

False

Explanation:

If the row echelon form of the augmented matrix for a linear system has a row of zeros, then the there must not have infinitely many solution,

we can prove this with an example. Suppose we have an augmented matrix A for linear system with a row of zeros,

1 0 0 1

A= 0 1 0 -2

0 0 1 - 1

0 0 0 0

we get

x1=1

x2=-2

x3=-1

so, system has an unique solution.

we can take inference that the given statement is wrong

7 0

3 years ago

Fill in the coefficients that will balance the following reaction:

andrey2020 [161]

Answer:

CH4 + 2 O2 → CO2 + 2 H2O

Explanation:

There are one mole of O2 on the left side and on the right side there are three moles of O2. And to fix it you would need to make it two moles of O2 to have four molecules of O2 on the left side. Then you would make two moles of H2O to have a total of four moles of O2 on the right. Therefore, CH4 + 2 O2 → CO2 + 2 H2O is the answer.

7 0

3 years ago

Read 2 more answers

Sodium sulfate is slowly added to a solution containing 0.0500 M Ca 2 + ( aq ) and 0.0390 M Ag + ( aq ) . What will be the conce

levacccp [35]

The given question is incomplete. The complete question is as follows.

Sodium sulfate is slowly added to a solution containing 0.0500 M $Ca^{2+}(aq)$ and 0.0390 M $Ag^{+}(aq)$ . What will be the concentration of $Ca^{2+}$ (aq) when $Ag_{2}SO_{4}(s)$ begins to precipitate? What percentage of the $Ca^{2+}(aq)$ can be separated from the Ag(aq) by selective precipitation?

Explanation:

The given reaction is as follows.

$Ag_{2}SO_{4} \rightleftharpoons 2Ag^{+} + SO^{2-}_{4}$

$[Ag^{+}]$ = 0.0390 M

When $Ag_{2}SO_{4}$ precipitates then expression for $K_{sp}$ will be as follows.

$K_{sp} = [Ag^{+}]^{2}[SO^{2-}_{4}]$

$1.20 \times 10^{-5} = (0.0390)^{2} \times [SO^{2-}_{4}]$

$[SO^{2-}_{4}]$ = 0.00788 M

Now, equation for dissociation of calcium sulfate is as follows.

$CaSO_{4} \rightleftharpoons Ca^{2+} + SO^{2-}_{4}$

$K_{sp} = [Ca^{2+}][SO^{2-}_{4}]$

$4.93 \times 10^{-5} = [Ca^{2+}] \times 0.00788$

$[Ca^{2+}]$ = 0.00625 M

Now, we will calculate the percentage of $Ca^{2+}$ remaining in the solution as follows.

$\frac{0.00625}{0.05} \times 100$

= 12.5%

And, the percentage of $Ca^{2+}$ that can be separated is as follows.

100 - 12.5

= 87.5%

Thus, we can conclude that 87.5% will be the concentration of $Ca^{2+}(aq)$ when $Ag_{2}SO_{4}(s)$ begins to precipitate.

4 0

2 years ago

Check my answer plz!! 100 points. Tell me if they are wrong! 1. You have three elements, A, B, and C, with the following electro

Artyom0805 [142]

look good w small changes below:

Answer:

AB is an ionic compound. The electronegativity difference between A and B is greater.

AC is an ionic compound. The electronegativity difference between A and C is greater.

BC is a covalent compound because the electronegativity difference between C and B is small.

everything else look good!

6 0

3 years ago

Read 2 more answers

T/F___ At the eutectic composition, an alloy can solidify at a constant temperature.___ For effective dispersion strengthening,

azamat

Answer:

TRUE
FALSE
TRUE
FALSE
FALSE
TRUE

Explanation:

At the eutectic composition, an alloy can solidify at a constant temperature : TRUE . this is because at eutectic composition the type of reaction that takes place there is invariant reaction in its thermal equilibrium
For effective dispersion strengthening, the dispersed phase should be needle-like, as opposed to round : FALSE. because the rounded shape will not cause a crack.
Intermetallic compounds are usually hard and brittle : TRUE. because Intermetallic compounds prevents dislocation movements and this makes them brittle and hard
For the effective dispersion and strengthening, the dispersed phase should be continuous : FALSE. this is because the dispersed precipitate must be small and not continuous
Stoichiometric intermetallic compounds exist over a range of compositions : FALSE
Faster solidification results in smaller interlamellar spacing : TRUE

4 0

3 years ago