For the answer to the question above, since the triangle is isosceles, the two legs have equal length. The coordinates of two vertices are given
P(3,3)
Q(3,1)
Assuming that PQ and QR are the legs of equal length, the distance between Q and R must be the same as the distance between P and Q
d = √[(3-3)² + (3-1)²
d = 2
Therefore, the coordinates of P is
(5,1)
Consecutive numbers differ by one. So, if is the first, the three numbers are
The sum of the first and third integer is
Answer:
D
Step-by-step explanation:
sorry if i am incorrect but that is my best guess
Apply slip and slide
a^2-3a-4
(a-4)(a+1)
(a-2)(2a+1)
Find zeros
a-2=0
a=2
2a+1=0
2a=-1
a=-1/2
Final answer: {-1/2, 2}
Answer:
im going to have to go with V=2.14×10^{6}