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Paha777 [63]
3 years ago
15

Calculate the density of a substance in pen- nyweights per peck that has a volume of 0.333 hogsheads and a mass of 49.62 kg.

Physics
1 answer:
kirill115 [55]3 years ago
4 0
Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. We calculate as follows:

Density = 49.62 kg ( 1000 g / 1 kg ) (1 pw / 1.55 g ) / 0.333 hogsheads ( 238.5 L / 1 hogshead ) ( 1 peck / 9.091 L ) 

Density = 3664.41 pw / pk
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Explanation:

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What did isaac newton describe forces and motion
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4 years ago
Juri is tugging her wagon behind her on the way to... wherever her wagon needs to go. The wagon repair shop. She has a trek ahea
vitfil [10]

Answer:

W = 819152 J = 819.15 KJ

Explanation:

The work done by Juri can be given by the following formula:

W = FdCos\theta

where,

W = Work done = ?

F = Force = 200 N

d = distance = 5 km = 5000 m

θ = angle to horizontal = 35°

Therefore,

W = (200 N)(5000 m)Cos 35°

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5 0
3 years ago
A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec
Anit [1.1K]

Answer:

The charged particle will follow a circular path.

Explanation:

The magnetic force exerted on the charged particle due to the magnetic field is given by:

F=qvB sin \theta

where

q is the charge

v is the velocity of the particle

B is the magnetic field

\theta is the angle between v and B

In this problem, the velocity is perpendicular to the magnetic field, so \theta = 90^{\circ}, sin \theta=1 and the force is simply

F=qvB

Moreover, the force is perpendicular to both B and v, according to the right-hand rule. Therefore, we have:

- a force that is always perpendicular to the velocity, v

- a force which is constant in magnitude (because the magnitude of v or B does not change)

--> this means that the force acts as a centripetal force, so it will keep the charged particle in a uniform circular motion. So, the correct answer is

The charged particle will follow a circular path.

8 0
4 years ago
Suppose your car accelerates from rest to 9 m/s in 2 s. Assume that the acceleration is constant in this time interval. A. What
Stolb23 [73]

Answer :

(a) The acceleration of the car is, 4.5m/s^2

(b) The distance covered by the car is, 9 m

Explanation :  

By the 1st equation of motion,

v=u+at ...........(1)

where,

v = final velocity = 9 m/s

u = initial velocity  = 0 m/s

t = time = 2 s

a = acceleration of the car = ?

Now put all the given values in the above equation 1, we get:

9m/s=0m/s+a\times (2s)

a=4.5m/s^2

The acceleration of the car is, 4.5m/s^2

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2 ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity  = 0 m/s

t = time = 2 s

a = acceleration  of the car = 4.5m/s^2

Now put all the given values in the above equation 2, we get:

s=(0m/s)\times (2s)+\frac{1}{2}\times (4.5m/s^2)\times (2s)^2

By solving the term, we get:

s=9m

The distance covered by the car is, 9 m

3 0
3 years ago
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