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Paha777 [63]
3 years ago
15

Calculate the density of a substance in pen- nyweights per peck that has a volume of 0.333 hogsheads and a mass of 49.62 kg.

Physics
1 answer:
kirill115 [55]3 years ago
4 0
Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. We calculate as follows:

Density = 49.62 kg ( 1000 g / 1 kg ) (1 pw / 1.55 g ) / 0.333 hogsheads ( 238.5 L / 1 hogshead ) ( 1 peck / 9.091 L ) 

Density = 3664.41 pw / pk
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A ray of light traveling in water (n = 1.33) is incident at the flat surface of a block of glass (n = 1.60). If the incident ray
mel-nik [20]

Answer:

45.19^{\circ}

Explanation:

We are given that

n_1=1.33

n_2=1.6

\theta_1=58.6^{\circ}

We have to find the angle of refraction.

By Snell's law

n_1sin\theta_1=n_2sin\theta_2

Substitute the values

1.33sin58.6=1.6sin\theta_2

sin\theta_2=\frac{1.33sin58.6}{1.6}

sin\theta_2=0.7095

\theta_2=sin^{-1}(0.7095)=45.19^{\circ}

Hence, the angle mad by refracted ray in to the glass with normal=45.19^{\circ}

7 0
3 years ago
Which describes radioactive decay of a substance?
Margarita [4]
Radioactive decay is the loss of elementary particles from an unstable nucleus, ultimately changing the unstable element into another more stable element. There are five types of radioactive decay: alpha emission, beta emission, positron emission, electron capture, and gamma emission.
4 0
3 years ago
A small spinning asteroid is in a circular orbit around a star, much like the earth's motion around our sun. The asteroid has a
Fudgin [204]

Answer:

Temperature will be 305 K  

Explanation:

We have given The asteroid has a surface area A=7.70m^2

Power absorbed P = 3800 watt

Boltzmann constant \sigma =5.67\times 10^{-8}Wm/K^4

According to Boltzmann rule power radiated is given by

P=\sigma AT^4

3800=5.67\times 10^{-8}\times 7.70\times T^4

T^4=87.0381\times 10^8

T=305K

So temperature will be 305 K  

8 0
4 years ago
Two objects, X and Y, move toward one another and eventually collide. Object X has a mass of 2M and is moving at a speed of 2vo
Nady [450]

Answer:

The force exerted by X on Y is F to the right, and the force exerted by Yon X is F to the left.

Explanation:

There are two objects X and Y. Mass of object X is 2M, that is moving with a speed of 2v_o and that of object Y is M that is moving with a speed of v_o.

When both of the objects collide, the magnitude of the forces F the objects exert on each other is equal to :

The force exerted by X on Y is F to the right, and the force exerted by Yon X is F to the left using Newton's third law of motion. Hence, the correct option is (c).

3 0
3 years ago
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I
Papessa [141]

Answer:

The acceleration is   a = 3.45*10^{3} m/s^2

Explanation:

 From the question we are told that

         The radius is  d = 6.5 cm = \frac{6.5}{100} = 0.065 m

           The magnitude of the magnetic field is  B = 5.5 T

           The rate at which it decreases is  \frac{dB}{dt}  = 24.5G/s = 24.5*10^{-4} T/s

             The distance from the center of field is  r = 1.5 cm = \frac{1.5}{100} = 0.015m

  According to Faraday's law

          \epsilon = - \frac{d \o}{dt}

and   \epsilon = \int\limits  {E} \, dl

 Where  the magnetic flux \o = B* A

             E is the electric field  

             dl is a unit length

 So

         \int\limits  {E} \, dl = - \frac{d}{dt} (B*A)

         {E}  l = - \frac{d}{dt} (B*A)

Now l is the circumference of the circular loop formed by the magnetic field and it mathematically represented as  l = 2\pi r

A is the area  of the circular loop formed by the magnetic field and it mathematically represented as  A= \pi r^2

So

    {E}  (2 \pi r)= -  \pi r^2 \frac{dB}{dt}

    E = \frac{r}{2} [ - \frac{db}{dt} ]  

Substituting values  

    E = \frac{0.015}{2} (24*10^{-4})

         E = 3.6*10^{-5} V/m

The negative signify the negative which is counterclockwise

 

  The force acting on the proton is mathematically represented as

                       F_p = ma

        Also       F_p = q E

So

           ma = qE

 Where m is the mass of the the proton which has a value of  m = 1.67 *10^{-27} kg

 q = 1.602 *10^{-19} C

     So

            a =\frac{1.60 *10^{-19} *(3.6 *10^{-5}) }{1.67 *10^{-27}}

               a = 3.45*10^{3} m/s^2

                   

     

               

8 0
3 years ago
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