A 500 g ball swings in a vertical circle at the end of a 1.4-m-long string. when the ball is at the bottom of the circle, the tension in the string is 18 n.
Answer: C
Explanation: weak nuclear
I can't see numbers here, so here are all the answers:
1) the frequency is c/λ = 3e8/556e-9 = 5.39e14Hz
2) light travels at <span>299,792,458 m/s. So in nanoseconds it's 0.299792458m. This is about 1/3 of a meter which is about one foot.
3) length is L = ct = (</span>299,792,458 m/s)(6e-15) = 1.799e-6m or 1.799μm
We are given with two measurements of the arm and an input weight. To answer this problem,we need to balance the forces and use the lengths of the arms.
209 N * 8 m = x * 1.5 m
x = 1114.67 N
it takes 1114.67 N to lift the input weight
