All categories

2 years ago

How many joules are there in 200kj

Physics

2 answers:

timurjin [86]2 years ago

5 0

Answer:

$2.00 * 10^5J$

Explanation:

Make use of your conversion factors:

$200KJ * \frac{1000J}{1kJ} = 200,000J = 2.00* 10 ^5J$

Or alternatively make use of your scientific notation. $kilo = 10^3$

Therefore $200kJ = 200*10^3J=2.0*10^2*10^3J = 2.0*10^5J$

Lesechka [4]2 years ago

4 0

Answer:

200,000 joules <3

Explanation:
just accept it

You might be interested in

A beaker containing mercury is placed inside a vacuum chamber in a laboratory. the pressure at the bottom of the beaker is 26000

krok68 [10]

The mercury density (at liquid state) is
$\rho = 13.5 g/cm^3=13500 kg/m^3$

And we know that the pressure at the bottom of a column of fluid is given by (Stevin's law)
$p=\rho g h$
where
$\rho$ is the liquid density
g is the gravitational acceleration
h is the height of the column of fluid

The pressure at the bottom of the beaker is $p=26000 Pa$ , therefore we can re-arrange the previous equation to get the height of the column of mercury
$h= \frac{p}{\rho g}= \frac{26000 Pa}{(13500 kg/m^3)(9.81 m/s^2)}=0.196m = 19.6 cm$

5 0

3 years ago

Assemble the electromagnetic spectrum by dragging each piece to the correct place on the wavelength scale.

777dan777 [17]

Answer:

long wave with a frequency of nos 10⁶ Hz, to radio waves

* order of 10⁸ Hz TV and FM

* in the 10⁹ to 10¹¹ Hz microwave range

* in the range of 10¹² to 10¹⁴ infrared waves, thermal energy

* in the range of 10¹⁴ visible light captured by humans

* for range 10¹⁵ to 10¹⁸ UV light

* in the range of 10¹⁶ to 10²⁰ X-rays

* for more than 10¹⁹ Hz cosmic rays

Explanation:

The electromagnetic spectrum is formed by transverse waves that are the oscillations of electric and magnetic fields

c = λ f

in general this spectrum is divided into range depending on the uses of the waves

from lower frequency to higher we have

* long wave with a frequency of nos 10⁶ Hz, corresponds to radio waves

* tv wave and modulated frequency, of the order of 10⁸ Hz, television and FM radio

* in the 10⁹ to 10¹¹ Hz microwave range

* in the range of 10¹² to 10¹⁴ infrared waves,

* in the range of 10¹⁴ visible light captured by humans

* for range 10¹⁵ to 10¹⁸ UV light

* in the range of 10¹⁶ to 10²⁰ X-rays

* for more than 10¹⁹ Hz cosmic rays

6 0

3 years ago

12345678901234567890

melomori [17]

Answer:

Is this a question?

Explanation:

7 0

3 years ago

GIVING BRAINLIEST PLEASE HELP!!

alisha [4.7K]

Answer:

c is the right answer is it

6 0

3 years ago

A fire truck emits an 880Hz siren. As the truck approaches an observer on the sidewalk, he perceives the pitch to be 950Hz. Appr

Ludmilka [50]

Answer:

The pitch that he hears after the truck passes and is moving away is 819.6 Hz.

Explanation:

The pitch that he hears after the truck passes and is moving away can be calculated using the following equation:

$f = f_{0}*\frac{v_{s} \pm v_{o}}{v_{s} \pm v_{f}}$

Where:

$f$ : is the perceived frequency

$f_{0}$ : is the emitted frequency

$v_{s}$ : is the speed of sound = 340 m/s

$v_{o}$ : is the speed of the observer = 0 (he is not moving)

$v_{f}$ : is the speed of the fire truck

First, we need to find the speed of the fire truck. When it approaches the observer we have:

$f = f_{0}*\frac{v_{s} + v_{o}}{v_{s} - v_{f}}$

$950 Hz = 880 Hz*\frac{340 m/s}{340 m/s - v_{f}}$

$v_{f} = 340 m/s - \frac{880 Hz*340 m/s}{950 Hz}$

$v_{f} = 25.05 m/s$

Hence, the speed of the fire truck is 25.05 m/s.

Now, we can calculate the pitch that the observer hears after the truck passes:

$f = f_{0}*\frac{v_{s} - v_{o}}{v_{s} + v_{f}}$

$f = 880 Hz*\frac{340 m/s}{340 m/s + 25.05 m/s}$

$f = 819.6 Hz$

Therefore, the pitch that he hears after the truck passes and is moving away is 819.6 Hz.

I hope it helps you!

7 0

3 years ago