The higher the depth, the higher the mass of the liquid that creates pressure
For Fraunhofer diffraction at a single slit would be represented by:
<span>a sinθ = mλ
</span><span>It should be noted that the angle needs be halved because we are only concerned with the angle between m=1 and m=0 and they gave you the angle between m=1 to the right of the center and m=1 on the left of the center. We calculate as follows:
</span>
<span>a sin(45/2)=(1)(470)
a = 1228 nm
Hope this answers the question. Have a nice day.
</span>
Answer:
2.846m
Explanation:
The diver is performing projectile motion.
To find x(final), we are going to use the equation x(final) = v(initial)*t + x(initial)
x(initial) = 0
x(final) = ?
v(initial) = 2.3 m/s
we don't know t
To find t we will use y(final) = 1/2*(-9.8)*t^2 + v(initial in the y dir.)*t + y(initial)
- 9.8 in the acceleration in the y dir.
y(final) = 0
y(initial) = 7.5
v(initial in the y dir.) = 0
If we solve for t we get: t = 1.237s
Now we have all the components to solve for x(final) in x(final) = v(initial)*t + x(initial)
x(final) = 2.3*1.237 + 0
x(final) = 2.846m
Answer:
0.25
Explanation:
Magnification = image distance/object distance
mag = v/u.................. Equation 1
Given: f = -10 cm ( diverging lens) u = 30 cm.
Where can calculate for the value of v using
1/f = 1/u+1/v
make v the subject of the equation
v = fv/(u-f)..................... Equation 2
Substitute into equation 2
v = -30(10)/(30+10)
v = -300/40
v = -7.5 cm.
substituting into equation 1,
mag = 7.5/30
mag = 0.25
hence the magnification of the wretch = 0.25
