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4 years ago

2. Which energy sources (input) cause the solar panels to generate electrical energy?

Physics

1 answer:

Daniel [21]4 years ago

7 0

Answer:

Explanation:

<h2>In the case of artificial photosynthesis, the energy input used to generate the required electricity is solar energy. The optical solar energy is converted into electricity inside the material system using the same scientific principles as PV modules.</h2><h2>Hope it will help</h2>

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PLEASE HELP ASAP!! Nitrogen, Helium, and Neon would all be gases at room temperature; Why is this?

kvasek [131]

-- The boiling points of the first group are all at temperatures
that are way lower than a comfortable room.
. . . . . Nitrogen . . . -320° F
. . . . . Helium . . . . -452° F
. . . . . Neon . . . . . -411° F

The freezing points of the second group are all at temperatures
that are way higher than a comfortable room.
. . . . . Lithium. . . . . . 357° F
. . . . . Sodium . . . . . 208° F
. . . . . Potassium . . . 146 °F

7 0

3 years ago

a parent swings a 18.5 kg child in a circle of radius 1.05m, making 5 revolutions in 13.4s. what centripetal acceleration does t

Zolol [24]

Answer: $0.146 m/s^{2}$

Explanation:

The <u>centripetal acceleration</u> $a_{c}$ of an object moving in a uniform circular path is given by the following equation:

$a_{c}=\frac{V^{2}}{r}$ (1)

Where:

$V$ is the tangential velocity

$r=1.05 m$ is the radius of the circle

On the other hand, the tangential velocity is expressed as:

$V=\omega r$ (2)

Where $\omega$ is the angular velocity, which can be found knowing the child makes 5 revolutions in 13.4s:

$\omega=\frac{5 rev}{13.4 s}=0.37 rev/s$ (3)

Substituting (3) in (2):

$V=(0.37 rev/s)(1.05 m)$ (4)

$V=0.39 m/s$ (5)

Substituting (5) in (1):

$a_{c}=\frac{(0.39 m/s)^{2}}{1.05 m}$ (6)

Finally:

$a_{c}=0.146 m/s^{2}$

6 0

3 years ago

Read 2 more answers

Why can you still see<br>the Moon during an<br>eclipse?

love history [14]

During a total lunar eclipse, Earth completely blocks direct sunlight from reaching the Moon. The only light reflected from the lunar surface has been refracted by Earth's atmosphere. ... Due to this reddish color, a totally eclipsed Moon is sometimes called a blood moon.

3 0

4 years ago

Anna is sitting in a moving cart and throws a ball straight up. Theoretically, the ball should land in the cart, but it lands on

Likurg_2 [28]

Answer:

Reason for the difference in the ranges of the ball and the cart:

"the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

Explanation:

Assuming that the air friction is negligible.

Given that the ball lands on the ground a little before the cart.

So, the range of the ball is more than the range of the cart in the same time interval.

Let the instant speed of the cart is v m/s at the time of throwing the ball in the vertically upward direction, so the speed of the ball in the horizontal direction = v m/s.

Let t be the total time of flight of the ball.

As the gravitational force is acting in the downward direction so it will not change the horizontal velocity of the ball.

So, the range covered by the ball $= vt$ m.

Let u be the average speed of the cart for the time t s (same as the time of flight of ball).

So, the distance by the cart $= ut$ m

As the range of the ball is more than the range of the cart in the same time interval, so

$vt > ut \\\\\Rightarrow v>u.$

So, the reason for the difference in the ranges of the ball and the cart is "the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".

5 0

3 years ago

The ground electron configuration of a tc atom is [kr]5s24d5. what is the electron configuration of a tc3+ ion?

Sidana [21]

Answer

$[kr]4d^4$

Explanation

Given that the tc atom has electronic configuration $tc=[kr]5s^24d^5$ we find the electronic configuration of the ion as follows

Step 1

Because the 5s orbital is further away than the 4d from the nucleus , during the ionization process the two 5s electrons will be removed first. As as result the $tc^{2+}$ has electronic configuration $[kr]4d^5.$

Step 2

All that is left is to remove one more electron. This electron is removed from the 4d orbital. As a result, the $tc^{3+}$ ion has electronic configuration

$tc^{3+}=[kr]4d^4.$

8 0

4 years ago

Read 2 more answers