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AveGali [126]
3 years ago
12

SSA triangle problems may have zero, one, or two solutions, true of false?

Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

True.

Step-by-step explanation:

We use law of sine to solve the triangle when two sides and angle (SSA) is given.There are different cases possible .

1)  If a < b sin A.

In this case  No possible triangles or we can say there will be zero solutions.

2) If a > b sin A.

In this case there are   Two triangles possible.In such cases at least one of the solutions will be an obtuse triangle.

3) If a = b sin A.

We have   Unique solution or one solution.This is true for a right triangle.

Hence the given statement  SSA triangle problems may have zero, one, or two solutions is True.

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A cone with volume 2880 m³ is dilated by a scale factor of 1/4. What is the volume of the resulting cone?
labwork [276]
The volume of the cone is 2880 m3.
The scale factor is 1/4.
The volume of the cone has the formula (1/3)π r² h.
A scale factor of 1/4 will reduce the dimensions by 1/4 which will result to a total volume reduction of (1/4)³ = 1/64
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5 0
3 years ago
Read 2 more answers
Solve 0= 2t^3-21t^2+ 40t
sukhopar [10]
0=2t^3-21^2+40t
switch sides
2t^3-21t^2+40t=0
solve factoring 
t(t-8)(2t-5)=0
using the zero factor principle
t=0&#10;
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solve
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4 0
4 years ago
Using approciate properties find -4/7*3/5+4/7*-1/5+2/5*-4/5
slega [8]

Answer: 0.548

Step-by-step explanation:

First you need to remember the formula for PEMDAS(Parenthesis,exponents,multiplication,divison,addition,subtractio)

you can do either multiplication or divison whichever comes first, same with addition+subtraction.

the underlined means to simplify

1.<u>-0.57x3</u>/5+4/7x-1/5+2/5x-4/5

2.<u>-1.71/5</u>+4/7x-1/5+2/5x-4/5

3.-0.342+<u>4/7</u>x-1/5+2/5x-4/5

4.-0.342+0.57x<u>-1/5</u>+2/5x-4/5

5.-0.342+<u>0.57x-0.2</u>+2/5x-4/5

6.-0.342+0.114+<u>2/5</u>x-4/5

7.-0.342+0.114+<u>0.4x-4</u>/5

8.-0.342+0.114+<u>-1.6/5</u>

9.<u>-0.342+0.114</u>+-0.32

10.<u>-0.228+-0.32=-0.548</u>

<u>i did this all in one go so......</u>

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