An aircraft carrier left Hawaii one hour before a fishing boat. The ships traveled in opposite directions. The fishing boat trav
2 answers:
Answer: The speed of the aircraft carriers would be 28.33 mph.
Step-by-step explanation:
Since we have given that
Distance between the ships = 100 miles
Speed of the fishing boat = 5 mph
Number of hours = 6 hours
Let the speed of an air craft carrier be 'x'.
Since they are in opposite direction, so, our equation would be
Hence, the speed of the aircraft carriers would be 28.33 mph.
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Answer:
B.The exponent of the solution is –12, the difference of the original exponents.
C.The coefficient of the solution must be greater than or equal to one but less than 10.
D.The quotient is 3.0 ×
Step-by-step explanation:
We are finding the quotient of the expression below in scientific notation
The following conclusions can be drawn
B.The power of 10 in the solution is –12, the difference of the original exponents.
C.The coefficient is 3, which is greater than or equal to one but less than 10.
D.The quotient is 3.0 ×
Answer is QM = 18
You can find the length of QM by using Pythagorean theorem. See the attachment.
It is a quadrilateral with 4 equal congruent sides.
If SP = 30, so do the other 3 sides indicated by the tick marks on all 4 sides.
We will call side RQ = the hypotenuse
or side “c” = 30
We know RM is leg “b” = 24
Side “a” is our unknown QM
Our formula is
a^2 + b^2 = c^2
a^2 + 24^2 = 30^2
a^2 + 576 = 900
a^2 = 900 - 576
a^2 = 324
Take square root of both sides to solve a
a = 18
QM = 18
You can find the length of QM by using Pythagorean theorem. See the attachment.
It is a quadrilateral with 4 equal congruent sides.
If SP = 30, so do the other 3 sides indicated by the tick marks on all 4 sides.
We will call side RQ = the hypotenuse
or side “c” = 30
We know RM is leg “b” = 24
Side “a” is our unknown QM
Our formula is
a^2 + b^2 = c^2
a^2 + 24^2 = 30^2
a^2 + 576 = 900
a^2 = 900 - 576
a^2 = 324
Take square root of both sides to solve a
a = 18
QM = 18