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V125BC [204]
3 years ago
12

Define a variable and write an equation to model each situation. Then solve. Show your work. Tickets to the county fair for four

adults and five children cost $33.30. An adults ticket costs $1.50 more than a child's ticket. Find the cost of an adults ticket.
Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0
If x is the childrens ticket
4(x + 1.5) + 5x = 33.30 \\ 4x + 6 + 5x = 33.3 \\ 9x = 33.3 - 6 \\ 9x = 27.3 \\ x =  \frac{27.3}{6}  \\ x = 4.55
so that means that the adults ticket is
x + 1.50 = 4.55 + 1.50 = 6.05
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forsale [732]
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7 0
4 years ago
A shirt originally cost $39.39, but it is on sale for $27.57. What is the percentage decrease of the price of the shirt?
IgorLugansk [536]

30 percent decrease

Step-by-step explanation:

looking at this i know its a percent decrease

so how do we find percent decrease ?

first we subtract the first value 39.39 & the final value 27.57

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then we divide 11.82 by the first value

like this 11.82÷39.39 = 0.3000

then we multiply what we got by 100

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the way that most people mess up is when they divide sometimes they might do 39.39 divided by 11.82 instead of 11.82÷39.39.

3 0
3 years ago
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.
andreyandreev [35.5K]

The products of the polynomials are:

  • (xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
  • (2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
  • (x - y) * (x + 3y) = x² + 2xy + 3y²
  • (xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18
  • (x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6
  • (x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

<u>Pair 1: (xy + 9y + 2) and (xy – 3)</u>

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

<u>Pair 2: (2xy + x + y) and (3xy² - y)</u>

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

<u>Pair 3: (x – y) and (x + 3y) </u>

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

<u>Pair 4: (xy + 3x + 2) and (xy – 9) </u>

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9)  = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18

<u>Pair 5: (x² + 3xy - 2) and (xy + 3) </u>

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6

<u>Pair 6: (x + 3y) and (x – 3y)</u>

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

5 0
2 years ago
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